1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
san4es73 [151]
3 years ago
10

One of the numbers was increased by 10 and the other remained the same. How did the average of the two numbers change?

Mathematics
1 answer:
Alexxandr [17]3 years ago
6 0
10+0=10
10÷2=5
The average is 5.
You might be interested in
How many 2/3 cup servings are in 1/6 of a cup of popcorn? (in simplest fraction form) A) 1/2 B) 1/4 C) 2/3 D) 3/8
rusak2 [61]

Answer:

1/4 thus B: is your answer

Step-by-step explanation:

Simplify the following:

(1/6)/(2/3)

Multiply the numerator by the reciprocal of the denominator, (1/6)/(2/3) = 1/6×3/2:

3/(6×2)

3/6 = 3/(3×2) = 1/2:

1/(2×2)

2×2 = 4:

Answer:  1/4

7 0
3 years ago
Simplify: 3 5 power x 3-2power
natta225 [31]

Answer:

3 to the power of 5 is 243 and 3 to the power of 2 is 9 and

243 x 9 is 2187

Step-by-step explanation:

7 0
2 years ago
A random sample of 300 Americans planning long summer vacations in 2009 revealed an average planned expenditure of $1,076. The e
Rufina [12.5K]

Answer:

(1024.69,\ 1127.31)

Step-by-step explanation:

We know that the sample size was:

n = 300

The average was:

{\displaystyle {\overline {x}}}=1,076

The standard deviation was:

\s = 345

The confidence level is

1-\alpha = 0.99

\alpha=1-0.99\\\alpha=0.01

The confidence interval for the mean is:

{\displaystyle{\overline {x}}} \± Z_{\frac{\alpha}{2}}*\frac{s}{\sqrt{n}}

Looking at the normal table we have to

Z_{\frac{\alpha}{2}}=Z_{\frac{0.01}{2}}=Z_{0.005}=2.576

Therefore the confidence interval for the mean is:

1,076\± 2.576*\frac{345}{\sqrt{300}}

1,076\± 51.31

(1024.69,\ 1127.31)

This means that <em>the mean planned spending of all Americans who take long summer vacations in 2009 is between $ 1024.69 and $ 1127.31</em>

3 0
3 years ago
Initially a pool contains 340 gallons of water. A hose is placed in the pool, and the water is turned on. The hose adds 5.2 gall
Svetradugi [14.3K]

Answer: Amount of water that is turned in a minute is 5.2d. Given the fact that initially was 350 gallons of water everything you pour needs to be added to the initial amount. So the answer is V(x) = 350 + 5.2x   

thank me plz brainliest

Step-by-step explanation:

5 0
2 years ago
A trinidadian who is planning to visit Canada changed $3192 to canadian currency. How many $ did the triodion received
DanielleElmas [232]

Answer:

$3934

Step-by-step explanation:

We know that the currency of different countries are different.

So, one US dollar = 1.23 Canadian dollar

Given : $3192

A trinidadian changed some US dollar to Canadian dollar who plans to visit Canada.

He exchanged $3192.

Therefore,

1 US dollar = 1.23 Canadian dollar

The value of $ 3192 will be equal to = 1.23 x 3192

                                                            = $ 3933.96

                                                            ≈ $ 3934

Therefore,  triodion received =  $ 3934.

8 0
3 years ago
Other questions:
  • 12m/15m simplify this fraction
    11·1 answer
  • What is a number that when you multiply it by 6 and you subtract 4 from the product, you get 50?
    15·2 answers
  • 2. The sum of the third and the seventh terms
    5·1 answer
  • The sum of two numbers is 70. They differ by 11. What are the numbers?​
    13·2 answers
  • Whats the answer to the question
    5·2 answers
  • Please help quick! It is due in 20 min! Please help!
    10·1 answer
  • Evaluate 2 - (-4) + 3 + (-6) - (-2)
    13·1 answer
  • Brian, Pip and Sara share some sweets in the ratio 4:3:1. Brian gets 60 sweets. How many did
    8·1 answer
  • Write the slope-intercept form of equation of the line described.
    11·1 answer
  • Please help :( i don’t understand!
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!