Let a=price of adult ticket
let c=price of a child's ticket
start out by writing the following system of equations:
3a+4c=132
2a+3c=94
then, multiply the first equation by 2, and the second equation by 3 to get the following system of equations:
6a+8c=264
6a+9c=282
subtract the like terms to get the following equation:
-c=-18
divide both sides by -1 to get rid of the negative to get the price of a child's ticket to be $18. to find the price of an adult ticket, pick one of the original equations to substitute the 18 in for c to find a. for example:
2a+3c=94
2a+3(18)=94
2a+54=94
-54 -54
2a=40
2 2
a=20
or if you decide to use the other equation:
3a+4c=132
3a+4(18)=132
3a+72=132
-72 -72
3a=60
3 3
a=20
either way, you still get an adults ticket to be $20 and a child's ticket to be $18.
Answer:
A. (0,7)
B. -1.25
C. Negative
D. I started at (0,7), then plotted the second point by moving the point down 5 and right 4.
Step-by-step explanation:
Look at the equation more carefully.
I hope this helps :)
Answer:
(0,6)
Step-by-step explanation:
The given system of equations is
and
We substitute the first equation into the second equation to get:
We expand to get:
We group similar terms to get:
Put x=0 in to the first equation to get:
Therefore the solution is (0,6)
We know that the load is 8713 lbs.
The total weight (truck + load) is 17200 lb.
Then, we can calculate the weight of the empty truck as:
Answer: the empty truck's weight is 8487 lb.
T: empty truck's weight
W: total weight (loaded truck's weight)
L: Load
The equation is:
T = W - L
