(3)14. 32 ×21 = 96
8. 32
__. 64
112
112/96 <--the original answer
56/48
28/24
14/12
7/6 <--simplified answer
Answer: negative 1 minus another negitive 1 give you zero/X
Step-by-step explanation:
Answer:
The value of b is -5
Step-by-step explanation:
Answer:

Step-by-step explanation:
The work is define as the integral of the force times distance. So we have:

Now, we can write the force in terms of density.

V is the volume (V=2*1*1=2 m³)
So the work will be:

The limit of integration is between 0 and 0.5 because we want to pump half of the water out of the aquarium.


I hope it helps you!