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3 years ago

HELP PLEASE!! 30 POINTS!!

Mathematics

2 answers:

Vika [28.1K]3 years ago

8 0

Okay. So I am going to help you out. Just saying this is my first time.

agasfer [191]3 years ago

4 0

Your answer is A
hope this helped
to get this answer you multiply 475 by 1.75% and then you get 8.31

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An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo

Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = $\sqrt{A^{2} + B^{2} -2AB cos(c) }$

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = $\sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60) }$

C = $\sqrt{250000 + 90000 - [215000 cos(60) }]$

C = $\sqrt{340000 - [215000 * 0.5 }]$

C = $\sqrt{340000 - [107500 }]$

C = $\sqrt{232500}$

C = 482 km

The bearing can be gotten by using the Sine Rule.

$\frac{sina}{A}$ = $\frac{sinc}{C}$

sina/500 = sin60/482

482 sina = 500 sin60

sina = $\frac{500 sin60}{482}$

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0

3 years ago

15 = x + 4<br> whats the answer

stealth61 [152]

Answer:

Step-by-step explanation:

15-4 = x

15-4 = 11

x = 11

to isolate x, you move 4 to the other side and it becomes 15-4 = x

4 0

3 years ago

Una recta que pasa por los puntos A (2,1) y B (6,3) y otra recta pasa por A y por el punto (0,y) ¿Cuánto vale y, si ambas rectas

ASHA 777 [7]

The translation of the question given is

A line that passes through the points A (2,1) and B (6,3) and another line passes through A and through the point (0, y). What is y worth, if both lines are perpendicular?

Answer:

y = 5

Step-by-step explanation:

Line 1 that passes through A (2,1) and B (6,3)

Slope (m1) = 3-1/6-2 = 2/4 = 1/2

y - 1 = $\frac{1}{2}$ ( x -2)

2y - 2 = x- 2

y = $\frac{x}{2}$

Line 2 passes through A (2,1) and (0,y)

slope (m2) = $\frac{y-1}{-2}$

Line 1 and Line 2 are perpendicular

m1*m2 = -1

$\frac{1}{2}$ * $\frac{y-1}{-2}$ = -1

y-1 = 4

y = 5

slope = -2

Equation of Line 2

Y-1 = -2(x-2)

y -1 = -2x +4

2x +y = 5

7 0

2 years ago

5g−2≤ 3g+8 3g+8<br><br> it says to solve for g.

Bess [88]

Answer:g is greater than or equal to 6g + 18/5, or g >_ 6g + 18/5

Step-by-step explanation: 5G- 2 <_ 6g + 16

Add 2 to the 16. 5g <_ 6g + 18.

Divide 5 to both sides. g >_ 6g + 18/5

7 0

2 years ago

Find the value of n in the equation 6.2n – 3.7n = 85 + 45.

Hoochie [10]

Answer:

D. 52

Step-by-step explanation:

Add 85 and 45 to get 130.

6.2n-3.7n=130

Subtract 3.7 from 6.2

2.5n=130

divide 130 by 2.5 to find n

N=52

8 0

3 years ago

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