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professor190 [17]
3 years ago
13

The area of a square mirror is 256 in2. A rectangular mirror has a width the same as the square mirror's width. Its length is tw

o inches longer than its width. What is the area of the rectangular mirror?
Mathematics
2 answers:
aliina [53]3 years ago
7 0
256 in2 = s2
sqrt(256) = 16 → side length = 16
rectangle width = 16, length = 16+2 → 18
18 x 16 = 288 in2
larisa86 [58]3 years ago
6 0

288 in squared

hope it helped!!!

lol


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An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the
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There is a 33.10% probability that there is at least one defective integrated circuit.

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Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem

The electonic product contains 40 integrated circuits, so n = 40.

The probability that any integrated circuit is defective is 0.01, so \pi = 0.01

What is the probability that there is at least one defective integrated circuit?

Either there is at least one defective integrated circuit, that is probability P(X > 0), or there are no defective integrated circuits, that is probability P(X = 0). The sum of these probabilities is decimal 1. We want to find P(X>0).

P(X > 0) + P(X = 0) = 1

P(X > 0) = 1 - P(X = 0)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

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P(X > 0) = 1 - P(X = 0) = 1 - 0.6690 = 0.3310

There is a 33.10% probability that there is at least one defective integrated circuit.

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