Sorry again... but i need help on this one too:(

Q1. Calculate the area and perimeter of the following ring where a = 7cm, b = 14cm (i) Area of Ring: (3) (ii) The perimeter of R

vlabodo [156]

Answer:

i) Area of the ring = 462cm²

ii) Perimeter of the ring = 132cm

A complete question related to this found at brainly (ID: 19152996) is stated below:

Calculate the area and perimeter of the following ring where a = 7cm, b = 14cm (i) Area of Ring (ii) The perimeter of Ring

Find attached the diagram.

Step-by-step explanation:

a= smaller radius = 7cm

b= bigger radius = 14cm

i) Area of the ring = Area of larger circle - Area of smaller circle

Area of circle = Area of a ring = πr²

π =22/7

Area of larger circle = (22/7)(14)² = 22×28

Area of larger circle = 616cm²

Area of smaller circle = (22/7)(7)² = 22×7

Area of smaller circle = 154cm²

Area of the ring = 616 - 154 = 462cm²

ii) Perimeter of ring = Perimeter of larger circle + Perimeter of smaller circle

Perimeter of circle = 2πr

When r = 7cm and π = 22/7

Perimeter of smaller circle = 2×(22/7)×7 = 2×22

Perimeter of smaller circle = 44cm

When r = 14cm and π = 22/7

Perimeter of larger circle = 2×(22/7)×14 = 4×22

Perimeter of larger circle = 88cm

Perimeter of ring = 88+44 = 132cm

3 0

3 years ago

Factor completely 3x^4 - 3x ^3 - 18x ^2. Which of the following is one of the factors?

Otrada [13]

Answer:

$3x^4 - 3x ^3 - 18x ^2=3x^2(x+2)(x-3).$

Step-by-step explanation:

The expression $3x^4 - 3x ^3 - 18x ^2$ consists of three terms:

$3x^4;$
$-3x^3;$
$-18x^2.$

These three terms have common factor $3x^2.$ Thus,

$3x^4 - 3x ^3 - 18x ^2=3x^2(x^2-x-6).$

Consider the expression $x^2-x-6.$ You can rewrite it as

$x^2-x-6=x^2+2x-3x-6=x(x+2)-3(x+2)=(x+2)(x-3).$

The whole expression takes look

$3x^4 - 3x ^3 - 18x ^2=3x^2(x+2)(x-3).$

7 0

3 years ago

Solve triangles using the law of cosines<br> Find m angleB.<br> Round to the nearest degree,

andrey2020 [161]

Answer:

Step-by-step explanation:

CosB = ((15^2) + (8^2) - (14^2)) / (-2(15)(8))

cosB = 93 / -240

Take inverse cosine:

113°

5 0

3 years ago

Could the equation. For the graph of the function have degree 4?explain

aivan3 [116]

The graphed polynomial seems to have a degree of 2, so the degree can be 4 and not 5.

<h3>Could the graphed function have a degree 4?</h3>

For a polynomial of degree N, we have (N - 1) changes of curvature.

This means that a quadratic function (degree 2) has only one change (like in the graph).

Then for a cubic function (degree 3) there are two, and so on.

So. a polynomial of degree 4 should have 3 changes. Naturally, if the coefficients of the powers 4 and 3 are really small, the function will behave like a quadratic for smaller values of x, but for larger values of x the terms of higher power will affect more, while here we only see that as x grows, the arms of the graph only go upwards (we don't know what happens after).

Then we can write:

y = a*x^4 + c*x^2 + d

That is a polynomial of degree 4, but if we choose x^2 = u

y = a*u^2 + c*u + d

So it is equivalent to a quadratic polynomial.

Then the graph can represent a function of degree 4 (but not 5, as we can't perform the same trick with an odd power).

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

5 0

3 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2+y2=(2x2+2y2−x)2(012

Tomtit [17]

Im not completly sure but desmos.com is amazing for this stuff

5 0

3 years ago