You can't she do the same thing to me like I just be answering question for points and they mostly be correct and she just be deleting the questions like crazy.

3 0

2 years ago

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The area, a, of an ellipse can be determined using the formula a=TTxy where x and y are half the lengths of the largest and smal

Brilliant_brown [7]

$a=\pi xy$

To solve for y, divide both sides by $\pi x$ :

$y=\frac{a}{\pi x}$

6 0

3 years ago

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HELLLPPPP I need a explication on whether or not these angle relationships are possible

lisov135 [29]

Answer:

Step-by-step explanation:

5x+30 is a corresponding angle with 4x-9 so set them equal to each other. 4x-9+2x+3 will equal 180

4 0

3 years ago

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Since BC is parallel to DE, triangles ABC and ADE are similar. What are the lengths of the unknown sides? It would be a great he

bija089 [108]

Answer: AC= 10 cm and CE= 5 cm

Step-by-step explanation:

In the given picture, Δ ADE is a right triangle

∴ By Pythagoras theorem,

$AD^2+DE^2=AE^2\\\Rightarrow\ (8+4)^2+9^2=AE^2\\\Rightarrow\ AE^2=12^2+9^2\\\Rightarrow\ AE^2=144+81=225\\\Rightarrow\ AE=15\ cm$

Since triangles ABC and ADE are similar and corresponding sides of similar triangles are proportional therefore,

$\frac{AB}{AC}=\frac{AD}{AE}\\\Rightarrow\frac{8}{AC}=\frac{12}{15}\\\Rightarrow\ AC=\frac{8\times15}{12}\\\Rightarrow\ AC=10\ cm$

Now, AE=AC+CE

⇒CE=AE-AC

⇒CE=15-10=5 cm

4 0

3 years ago