Answer:
The solution of a system of linear equations is:
D. The values of the variables that satisfy both equations.
You isolate the v and move 3 units down to the left which leads u to 10. Hope this helped
A point that bisects a segment would be its midpoint. This is a case where the vocabulary (bisect as opposed to midpoint) makes it harder.
To find the midpoint, we use the midpoint formula. The midpoint formula is:
midpoint = (x₁ + x₂/2, y₁ + y/2). To find it, you add the x coordinates and then divide them by 2. Repeat for the y coordinates.
x: (-2 + 6)/2 = 4/2 = 2
y: (5 +1)/2 = 6/2 = 3
Thus the point B bisecting AC is at (2, 3).
Answer:
a) W₁ = 78400 [J]
b)Wt = 82320 [J]
Step-by-step explanation:
a) W = ∫ f*dl general expression for work
If we have a chain with density of 10 Kg/m, distributed weight would be
9.8 m/s² * 10 kg = mg
Total length of th chain is 40 m, and the function of y at any time is
f(y) = (40 - y ) mg where ( 40 - y ) is te length of chain to be winded
At the beggining we have to wind 40 meters y = 0 at the end of the proccess y = 40 and there is nothing to wind then:
f(y) = mg* (40 - y )
W₁ = ∫f(y) * dy ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy
W₁ = mg [ 40*y |₀⁴⁰ - 1/2 * y² |₀⁴⁰ ⇒ W₁ = mg* [ 40*40 - 1/2 (40)² ]
W₁ = mg * [1/2] W₁ = 10*9,8* ( 800 )
W₁ = 78400 [J]
b) Now we can calculate work to do if we have a 25 block and the chain is weightless
W₂ = ∫ mg* dy ⇒ W₂ = ∫₀⁴⁰ mg*dy ⇒ W₂ = mg y |₀⁴⁰
W₂ = mg* 40 = 10*9.8* 40
W₂ = 3920 [J]
Total work
Wt = W₁ + W₂ ⇒ Wt = 78400 + 3920
Wt = 82320 [J]
