Answer:
The length of the side PC is 34 cm.
Step-by-step explanation:
We are given that BP is the perpendicular bisector of AC. QC is the perpendicular bisector of BD. AB = BC = CD.
Suppose BP = 16 cm and AD = 90 cm.
As, it is given that AD = 90 cm and the three sides AB = BC = CD.
From the figure it is clear that AD = AB + BC + CD
So, AB = 
= 30 cm
BC = = 30 cm
CD = = 30 cm
Since the triangle, BPC is a right-angled triangle as 
PBC = 90°, so we can use Pythagoras theorem in this triangle to find the length of the side PC.
Now, the Pythagoras theorem states that;
= 1156
PC = 34 cm
Hence, the length of the side PC is 34 cm.
Answer:
the price went up 44.44%
Step-by-step explanation:
200÷450×100
the answer you're looking for, rounded to the nearest thousandth, is 0.006 and we get that answer because we must round 0.0057 to the nearest thousandth, meaning that we must look at the seven, and realize that the seven tells us that the 5 is supposed to be a 6 because we are rounding to the nearest thousandth. So the answer is 0.006 I hope that this helps!
Answer:
The answer is below
Step-by-step explanation:
Speed is the time rate of change of velocity, it is the ratio of distance to time.
Mr. Fowles runs at a steady 4.2 miles per hour. The time taken to cover 26 miles is:
speed = distance / time
time = distance / speed = 26 / 4.2 = 6.19 hour
I run at 3 miles per hour. I was given 3 mile lead, so the remaining distance is 23 miles (26 - 3). The time needed to complete the 23 miles is:
time = distance / speed = 23 / 3 = 7.67 hour
a) Let d be the distance Mr Fowles catches me. Hence:
time = (d + 3)/4.2; also time = d/3
(d + 3)/4.2 = d/3
3d + 9 = 4.2d
1.2d = 9
d = 7.5 miles
He would catch me at 10.5 (7.5 + 3) miles from the starting point.
b) Mr. fowles finishes after 6.19 hour. At that time, the distance is have covered is:
distance = 6.19 * 3 mi/hr = 18.57 mile
Distance behind = 23 mile - 18.57 = 4.43 mile
c) time longer = 7.67 hour - 6.19 hour = 1.48 hour
