Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
Answer:
6.7 * (10^7) = 67 000 000
Answer:
p^(m+n)
Step-by-step explanation:
p^m * p^n
We know that when they are multiplied when the bases are the same, we add the exponents
p^(m+n)
Answer:
B. (3,0)
Step-by-step explanation:
The x-intercept is the point where the graph of the function meets the x-axis.
At x-intercept, <u>y = 0 or f(x) = 0</u>
So look through the table and find where <u>f(x) = 0.</u>
From the table, <u>f(x) = 0 at x = 3.</u>
We write this as an ordered pair.
Therefore the x-intercept is <u>(3,0)</u>
The correct choice is <u>B</u>.
Answer:
Goodluck I had this before and couldn't get it
