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Juli2301 [7.4K]
3 years ago
7

Marcella bought a 25-ounce bottle of olive oil for $5.88. She used 60% of the olive oil in two weeks. What is the cost of the pe

rcentage of oil she used?
Mathematics
1 answer:
horrorfan [7]3 years ago
5 0
The answer is $3.53
$5.88 * 0.60 = 3.528
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Which expression calculates the time in hours an object takes to travel 38 miles at a speed of 2 m/h ? (I NEED HELP ASAP)
defon

Answer:

Option B : 38/2 is the correct answer.

Step-by-step explanation:

Given that:

Distance to travel = 38 miles

Speed of object = 2 miles per hour

Distance = Speed * Time

To find the time, we will divide the distance by speed.

Time = \frac{Distance}{Speed}

Putting values of distance and speed in the formula.

Time = 38/2

Hence,

Option B : 38/2 is the correct answer.

4 0
3 years ago
A math problem asks when two brothers will have saved the same amount of money. When Marta writes and solves the equation, her f
Korolek [52]

Answer:

B. The brothers will never have the same amount of money.

Step-by-step explanation:

When we get to the final step and get 3=7, which we know it not true, this means there is no solution.

3 0
4 years ago
Read 2 more answers
(-7a+7b-1)-(a+8) find the difference
aalyn [17]

Answer: -8a+7b-9


Step-by-step explanation:

(-7a+7b-1)-(a+8)

-7a+7b-1-a-8 (distributive property)

-8a+7b-9 (combine like-terms)

8 0
4 years ago
Read 2 more answers
It is known that there only is 1% chance of getting a disease. a test is being devised to detect the disease. the probability th
Cerrena [4.2K]
Suppose D is the event that a given patient has the disease, and P is the event of a positive test result.

We're given that

\mathbb P(D)=0.01
\mathbb P(P\mid D)=0.98
\mathbb P(P^C\mid D^C)=0.95

where A^C denotes the complement of an event A.

a. We want to find \mathbb P(P^C). By the law of total probability, we have

\mathbb P(P^C)=\mathbb P(P^C\cap D)+\mathbb P(P^C\cap D^C)

That is, in order for P^C to occur, it must be the case that either D also occurs, or D^C does. Then from the definition of conditional probability we expand this as

\mathbb P(P^C)=\mathbb P(D)\mathbb P(P^C\mid D)+\mathbb P(D^C)\mathbb P(P^C\mid D^C)

so we get

\mathbb P(P^C)=0.01\cdot0.02+0.99\cdot0.95=0.9407

b. We want to find \mathbb P(D\mid P). Now, we can use Bayes' rule, but if you're like me and you find the formula a bit harder to remember, we can easily derive it.

By the definition of conditional probability,

\mathbb P(D\mid P)=\dfrac{\mathbb P(D\cap P)}{\mathbb P(P)}

We have the probabilities of P/P^C occurring given that D/D^C occurs, but not vice versa. However, we can expand the probability in the numerator to get a probability in terms of P being conditioned on D:

\mathbb P(D\cap P)=\mathbb P(D)\mathbb P(P\mid D)

Meanwhile, the law of total probability lets us rewrite the denominator as

\mathbb P(P)=\mathbb P(P\cap D)+\mathbb P(P\cap D^C)

or in terms of conditional probabilities,

\mathbb P(P)=\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)

so that

\mathbb P(D\mid P)=\dfrac{\mathbb P(D)\mathbb P(P\mid D)}{\mathbb P(D)\mathbb P(P\mid D)+\mathbb P(D^C)\mathbb P(P\mid D^C)}

which is exactly what Bayes' rule states. So we get

\mathbb P(D\mid P)=\dfrac{0.01\cdot0.98}{0.01\cdot0.98+0.99\cdot0.05}\approx0.1653
6 0
3 years ago
Plzzz help as soon as possible
Anika [276]

Answer:

Step-by-step explanation:

8 is not a function

9 is a function

10 is a function

4 0
3 years ago
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