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2 years ago

Find the sum of the first 30 multiples of 8.

Mathematics

1 answer:

Anna11 [10]2 years ago

3 0

Step-by-step explanation:

sum of the arithmetic sequence

a1 = 8

a2 = a1 + 8 = 8+8 = 16

...

an = 8×n

the sum of the first n elements of such a series is

n/2 × (2×a1 + (n - 1)×d]

with d being the difference between 2 consecutive elements (= the added constant).

so,

s30 = 30/2 × (2×8 + 29×8) = 15×(31×8) = 3720

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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Mrac [35]

Answer:

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Step-by-step explanation:

here's the solution :-

=》

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=》

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3 years ago

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