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Stells [14]
3 years ago
11

The tire of his unicycle has a circumference of 2.8m , point,, and the tire revolves 1.51.51, point, 5 times per second. What is

the distance Benjamin travels in 100100100 seconds?
Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0

Answer:

Benjamin travels 7 meters in 100 seconds.    

Step-by-step explanation:

We are given the following in the question:

Circumference of tire = 2.8 m

Revolution of time = 1.5 times per minute.

Total time = 100 seconds.

We have to calculate distance covered by Benjamin.

Total number of revolution of tires =

=\text{Revolution rate}\times \text{Time}\\\\=1.5\text{ revolution per minute}\times \dfrac{100}{60}\text{ minutes}\\\\=2.5 \text{ revolutions}

Total distance covered by Benjamin =

=\text{Number of revolution of tires}\times \text{Circumference of tire}\\=2.5\times 2.8\\=7\text{ meters}

Thus, Benjamin travels 7 meters in 100 seconds.

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kaheart [24]

Answer:

  First "order of operations" mistake: step 2

  First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

__

We expect your answer is supposed to be Step 4.

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3 years ago
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Leokris [45]

Answer:

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Step-by-step explanation:

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Question 1 (Essay Worth 10 points) (01.02 MC) Part A: If (26)x = 1, what is the value of x? Explain your answer. (5 points) Part
katen-ka-za [31]

Answer:

See Explanation

Step-by-step explanation:

The question is not clear. However, I will treat the question as:

(26)x = 1

(50)x = 1

and:

(2^6)^x = 1

(5^0)^x = 1

Solving: (26)x = 1  and  (50)x = 1

(26)x = 1

Divide both sides by 26

x = \frac{1}{26}

(50)x = 1

Divide both sides by 50

x = \frac{1}{50}

Solving (2^6)^x = 1 and (5^0)^x = 1

(2^6)^x = 1

Express 1 as 2^0

(2^6)^x = 2^0

Remove bracket

2^{6x} = 2^0

Cancel out 2

6x = 0

Divide both sides by 6

x = \frac{0}{6}

x = 0

(5^0)^x = 1

Express 1 as 5^0

(5^0)^x = 5^0

Cancel out 5^0

x = 1

8 0
3 years ago
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