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pantera1 [17]
3 years ago
12

How do you put -6 + 9 in a number line?

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0
Ok, so you either put positive 3 on the number line, or you start at -6, and then draw a line (above the actual number line) to positive 9. 
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In a two digit number, t = the tens digit and u = the ones digit. Which of the expressions below shows the value of its reversal
Leni [432]

10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit. This can be obtained by multiplying 10 with the tens digit and adding unit digit.

<h3>Which is the required expressions?</h3>

Given that, in a two digit number,

t = the tens digit

u = the ones digit

The expression for the digit will be ,

10×t + u = 10t + u

The value of its reversal,

u = the tens digit

t = the ones digit

10×u + t = 10u + t is the required expression

For example,

37 = 10×3 + 7 = 30 + 7 and its reverse 73 = 10×7 + 3 = 70 + 3

Hence 10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit.

Learn more about algebraic expressions here:

brainly.com/question/19245500

#SPJ1

4 0
1 year ago
helpppppp please I need help on this question if you can explain i will give brainliest if you can't then font please ​
lara [203]

Answer:

The answer is A

Step-by-step explanation:

Down 2 right 3. You can figure this out for other problems like this by choosing any point on the graph and following the slope. It's down because the 2 is negative and 3 is positive to it goes to the right.

5 0
2 years ago
(- 1, 2) and (9, - 3)
slava [35]

9/5

the distance is 9 over, and 5 up.

5 0
3 years ago
Read 2 more answers
HELP ME PLEASE I BEG YOU I REALLY NEED HELP !!!
oee [108]
To find the size of each angle, divide the sum, 540º, by the number of angles in the pentagon. (which is the same as the number of sides). There are 108° in each interior angle of a regular pentagon. This process can be generalized into a formula for finding each interior angle of a REGULAR polygon ...
4 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
2 years ago
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