How do you put -6 + 9 in a number line?

1 answer:

5 0

Ok, so you either put positive 3 on the number line, or you start at -6, and then draw a line (above the actual number line) to positive 9.

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How do you solve this problem and what is the answer?

Zanzabum

Well, using a+b=c , it would mean that 12+b=35. therefore b would equal 23 if that’s what you’re looking for

4 0

2 years ago

NEED HELP NOWW!!! Andre is in charge of cooking broccoli and zucchini for a large group. He has to spend all $17 he has and can

Nookie1986 [14]

Answer:

a. 9 pounds of broccoli and 1 pound of zucchini

b. 7lbs broccoli and 2 lbs of zucchini

c. 6lbs zucchini and 4lbs broccoli.

Step-by-step explanation:

a. well just come up with 2 numbers that equal up to 10 so yea.

b. 7lbs broccoli 2 lbs of zucchini - this is 9 lbs of veggies but it costs 17 dollars because (7*2)+(2*1.50)=17

14+3=17 (the 7 and 2 is the amount of pounds of veggies and the 2 and 1.50 are the prices)

c. it would be 6 lbs of zucchini and 4 lbs of broccoli because 6+4=10 and (6*1.50)+(4*2)=17

7 0

2 years ago

Read 2 more answers

When 27x^2z/-3x^2z^6 is completely simplified , the exponent on the variable z is _____

-BARSIC- [3]

$\bf \cfrac{27x^2z}{-3x^2z^6}\implies -\cfrac{27}{3}\cdot \cfrac{x^2z}{x^2z^6}\implies -9\cdot \cfrac{x^2x^{-2}}{z^6z^{-1}}\implies -9\cdot \cfrac{x^{2-2}}{z^{6-1}}
\\\\\\
-9\cdot \cfrac{x^0}{z^5}\implies -9\cdot \cfrac{1}{z^5}\implies -\cfrac{9}{z^5}$