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Tju [1.3M]
3 years ago
8

3942588 to the nearest thousand

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
6 0
3,943,000 I am not really good at this, but I think this is the answer. 


miss Akunina [59]3 years ago
4 0
3,944,000
Hope it helps
Enjoy<3


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5x-2y=11 and 3x+4y=4<br>Find the value of x and y in equation.​
nadya68 [22]
  • 5x-3y=11---(1)
  • 3x+4y=4---(2)

(1)×3 and (2)×5

  • 15x-9y=33-(3)
  • 15x+20y=20-(4)

Subtract both

\\ \sf\longmapsto -29y=13

\\ \sf\longmapsto y=\dfrac{-13}{29}

  • Put in eq(1)

\\ \sf\longmapsto 5x+\dfrac{-117}{29}=11

\\ \sf\longmapsto 5x=11+\dfrac{117}{29}=\dfrac{261+117}{29}=\dfrac{278}{29}

\\ \sf\longmapsto x=\dfrac{278}{145}

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2 years ago
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Work out the gradient of the graph shown.
icang [17]

y=-3 and then x=-1 =-3:-1

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3 years ago
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podryga [215]

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Step-by-step explanation:

8 0
4 years ago
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-6(p+8)=36<br><br> Algebra two step equation
Tatiana [17]

Answer:

The value of p = -14

Step-by-step explanation:

Given the equation

-6\left(p+8\right)=36

Divide both sides by -6

\frac{-6\left(p+8\right)}{-6}=\frac{36}{-6}

simplify

p+8=-6

Subtract 8 from both sides

p+8-8=-6-8

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8 0
3 years ago
The dimensions of rectangle A are four times the dimensions of rectangle B. The area of rectangle B is 162 cm2. What is the area
Anna [14]

Answer:

2,592 square cm.

Step-by-step explanation:

It is given that the dimensions of rectangle A are four times the dimensions of rectangle B.

Let dimensions of rectangle B are l×b.

So, the dimensions of rectangle A are 4l×4b.

Area of rectangle is

Area=length\times width

Area of rectangle B is

A_B=l\times w

The area of rectangle B is 162 square cm.

A_B=l\times w=162

Area of rectangle A is

A_A=4l\times 4w=16(l\times w)=16(162)=2592

Therefore, the area of rectangle A is 2,592 square cm.

3 0
3 years ago
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