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Marizza181 [45]
2 years ago
12

Which of the following characteristics does not describe a stock?

Mathematics
2 answers:
kipiarov [429]2 years ago
8 0

hi

it'b :  If you earn money from a coupon, it's mean that you  lentmoney to somenone.in  In stocks, there is no  coupon.  The annual meeting of stock holders will decide how much is  given for each share by considering annual profit made by the compagny.

WITCHER [35]2 years ago
6 0

Answer:

B. Money earned from coupon rate

Step-by-step explanation:

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Which formula is easier to use. Finding the area of a trapezoid or circle? Explain in detail with a minimum of 4 sentence
Scrat [10]

Answer: Circle, in my opinion

Step-by-step explanation:

Trapezoid Formula: (a+b/2)h

Circle Formula: πr*2

Solving a circle requires less steps than solving for a trapezoid would, so in my opinion, finding the area of a circle is easier than a trapezoid.

Hope this helps!

8 0
2 years ago
How do organism replace dead or injured cells? Organisms can take cells from other organisms. Organisms are limited to the amoun
Gnoma [55]

Answer: Organisms go through mitosis that allows new identical cells to be made.

explanation:

mitosis also occures when cells are worn out or are injured and the mitosis will replace the injured cells

8 0
3 years ago
3. Let A, B, C be sets and let ????: ???? → ???? and ????: ???? → ????be two functions. Prove or find a counterexample to each o
Fiesta28 [93]

Answer / Explanation

The question is incomplete. It can be found in search engines. However, kindly find the complete question below.

Question

(1) Give an example of functions f : A −→ B and g : B −→ C such that g ◦ f is injective but g is not  injective.

(2) Suppose that f : A −→ B and g : B −→ C are functions and that g ◦ f is surjective. Is it true  that f must be surjective? Is it true that g must be surjective? Justify your answers with either a  counterexample or a proof

Answer

(1) There are lots of correct answers. You can set A = {1}, B = {2, 3} and C = {4}. Then define f : A −→ B by f(1) = 2 and g : B −→ C by g(2) = 4 and g(3) = 4. Then g is not  injective (since both 2, 3 7→ 4) but g ◦ f is injective.  Here’s another correct answer using more familiar functions.

Let f : R≥0 −→ R be given by f(x) = √

x. Let g : R −→ R be given by g(x) = x , 2  . Then g is not  injective (since g(1) = g(−1)) but g ◦ f : R≥0 −→ R is injective since it sends x 7→ x.

NOTE: Lots of groups did some variant of the second example. I took off points if they didn’t  specify the domain and codomain though. Note that the codomain of f must equal the domain of

g for g ◦ f to make sense.

(2) Answer

Solution: There are two questions in this problem.

Must f be surjective? The answer is no. Indeed, let A = {1}, B = {2, 3} and C = {4}.  Then define f : A −→ B by f(1) = 2 and g : B −→ C by g(2) = 4 and g(3) = 4. We see that  g ◦ f : {1} −→ {4} is surjective (since 1 7→ 4) but f is certainly not surjective.  Must g be surjective? The answer is yes, here’s the proof. Suppose that c ∈ C is arbitrary (we  must find b ∈ B so that g(b) = c, at which point we will be done). Since g ◦ f is surjective, for the  c we have already fixed, there exists some a ∈ A such that c = (g ◦ f)(a) = g(f(a)). Let b := f(a).

Then g(b) = g(f(a)) = c and we have found our desired b.  Remark: It is good to compare the answer to this problem to the answer to the two problems

on the previous page.  The part of this problem most groups had the most issue with was the second. Everyone should  be comfortable with carefully proving a function is surjective by the time we get to the midterm.

3 0
3 years ago
Help me *welp
ira [324]

Answer:

3332

Step-by-step explanation:

6 0
3 years ago
X + 8 &lt; 10<br> Please help
Cerrena [4.2K]

Answer:

if I'm solving for x, then its 2

(I think)

6 0
2 years ago
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