All categories

3 years ago

Which property is illustrated by the following statement? 5g+7= 7 + 5g

Mathematics

2 answers:

nikdorinn [45]3 years ago

4 0

Commutative property

Arada [10]3 years ago

4 0

Answer:

The property which is illustrated by the statement 5g+7= 7 + 5g is:

Commutative property

Step-by-step explanation:

Commutative property states that:

If a and b are two elements defined under the operation *

Then, a*b=b*a

Here, we are given

5g+7= 7 + 5g

i.e. a=5g, b=7 and * = +

Hence, the property which is illustrated by the statement 5g+7= 7 + 5g is:

Commutative property

You might be interested in

A speed of 220 feet per minute is equal to how many miles per hour

garik1379 [7]

Answer: 2.5 miles per hour

Step-by-step explanation:

this problem is all about conversions

220 ft per minute

first get it to hours, since there is 60 minute in an hour multiply by a factor of 60

220 ft per minute becomes 13200 ft per hour

then you need to covert from ft to mi, there are 5280 ft in 1 mi so divide by 5280

13200 ft per hour becomes 2.5 miles per hour

3 0

3 years ago

Solve the system. 3x + 4y = 7 2x-y=1 What does x and y equal

emmainna [20.7K]

Answer:

x=1 y=1

Step-by-step explanation:

Let's use the elimination method.
3x+4y=7
2x-y = 1 (multiply both sides by 4)
8x-4y=4
3x+4y=7

(add both equations together)
11x=11
x=1
Plug x=1 into either of the equations
2(1) - y=1
2-y=1
2=1+y
y=1

5 0

2 years ago

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then

7=-4·2+b,

b=7+8,

b=15.

Answer 4: y=-4x+15.

Part E. Consider vectors $\vec{p}_1=(-c-0,0-(-d))=(-c,d)\quad \text{and}\quad \vec{p}_2=(0-b,a-0)=(-b,a).$ These vectors are collinear, then

$\dfrac{-c}{-b}=\dfrac{d}{a},\quad \text{or}\quad -\dfrac{a}{b}=-\dfrac{d}{c}.$

Answer 5: $-\dfrac{a}{b}=-\dfrac{d}{c}.$

5 0

3 years ago

Read 2 more answers

5/6 of 15 i need help????????????

emmainna [20.7K]

Answer: 12.5 or 12 1/2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which transformations can be used to map a triangle with vertices A(2, 2), B(4, 1), C(4, 5) to A’(–2, –2), B’(–1, –4), C’(–5, –4

jek_recluse [69]

Notice that every pair of point (x, y) in the original picture, has become (-y, -x) in the transformed figure.

Let ABC be first transformed onto A"B"C" by a 90° clockwise rotation.

Notice that B(4, 1) is mapped onto B''(1, -4). So the rule mapping ABC to A"B"C" is (x, y)→(y, -x)

so we are very close to (-y, -x).

The transformation that maps (y, -x) to (-y, -x) is a reflection with respect to the y-axis. Notice that the 2. coordinate is same, but the first coordinates are opposite.

ANSWER:

"a 90 clockwise rotation about the origin and a reflection over the y-axis"

5 0

3 years ago

Read 2 more answers