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Contact [7]
3 years ago
7

Is 0.5 greater than six tenths draw a number line to show your answer

Mathematics
2 answers:
AlladinOne [14]3 years ago
7 0
1/2_6/10 1/2_3/5 /*10 5 >6
Ivahew [28]3 years ago
4 0
0.6(six tenths) is definitely greater that 0.5 (five tenths)
You might be interested in
Given: ∆ABC –iso. ∆, m∠BAC = 120°
lidiya [134]

Answer: P\triangle ADH = (a+b+\sqrt{a^2+b^2} ) unit

Step-by-step explanation:

Since Here Δ ABC is a isosceles triangle.

Also, AH\perp BC and HD\perp AC

Thus, ∠ ADH = 90°

That is, Δ ADH is the right angle triangle.

In which, AD = a unit and HD = b unit

And, By the definition of Pythagoras theorem,

AH^2 = HD^2 + AD^2

⇒ AH^2 = a^2 +b^2

⇒ AH = \sqrt{a^2+b^2}

Since, the perimeter of a triangle = sum of the all sides of the triangle.

Therefore, perimeter of ΔADH = AD + DH + AH

= a + b + \sqrt{a^2+b^2} unit

4 0
3 years ago
Find the surface area of a sphere with a radius of 8cm
Andreas93 [3]
I believe the proper way to find the surface area of a sphere is 4 times 3.14 (which is Pi) times the radius squared. Or 4(3.14)*r^2.

Where I found 804.25
3 0
3 years ago
divide a x cubed space plus 3 x squared space minus b x minus 6 space b y space x to the power of 2 space end exponent plus 3 x
marta [7]

Answer:

ax^3+3x^2-bx-6/x^2+3x+2 ( Please specify the equation if I'm wrong)

Step-by-step explanation:

ax^3+3x^2-x^2-bx-3x-6-2

=ax^3+2x^2-x(b+3)-8

3 0
3 years ago
find the fraction of the area of a triangle that is occupied by the largest rectangular that can be drawn in the triangle (with
gogolik [260]

Answer:

½

Step-by-step explanation:

Draw a picture of the triangle with the rectangle inside it.

Let's say the width and height of the triangle are w and h (these are constants).

Let's say the width and height of the rectangle are x and y (these are variables).

The area of the triangle is ½ wh.

The area of the rectangle is xy.

Using similar triangles, we can say:

(h − y) / h = x / w

x = (w/h) (h − y)

So the rectangle's area in terms of only y is:

A = (w/h) (h − y) y

A = (w/h) (hy − y²)

We want to maximize this, so find dA/dy and set to 0:

dA/dy = (w/h) (h − 2y)

0 = (w/h) (h − 2y)

0 = h − 2y

y = h/2

So the width of the rectangle is:

x = (w/h) (h − y)

x = (w/h) (h − h/2)

x = (w/h) (h/2)

x = w/2

That means the area of the rectangle is:

A = xy

A = ¼ wh

The ratio between the rectangle's area and the triangle's area is:

(¼ wh) / (½ wh)

½

So no matter what the dimensions of the triangle are, the maximum rectangle will always be ½ its area.

6 0
3 years ago
Please Help! Thanks whoever can answer my question!
nlexa [21]
A function is a special relationship where each input has a single output.
therefore :
A is not a function; x=0;  ⇒y₁=3; y₂=4
C is not a function; x=2;⇒ y₁=1; y₂=8
D is not a function; x=1;⇒y₁=2, y₂=-3

only B is a function; each input has a single output. 


4 0
3 years ago
Read 2 more answers
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