Answer:
unit
Step-by-step explanation:
Since Here Δ ABC is a isosceles triangle.
Also,
and
Thus, ∠ ADH = 90°
That is, Δ ADH is the right angle triangle.
In which, AD = a unit and HD = b unit
And, By the definition of Pythagoras theorem,

⇒ 
⇒ 
Since, the perimeter of a triangle = sum of the all sides of the triangle.
Therefore, perimeter of ΔADH = AD + DH + AH
=
unit
I believe the proper way to find the surface area of a sphere is 4 times 3.14 (which is Pi) times the radius squared. Or 4(3.14)*r^2.
Where I found 804.25
Answer:
ax^3+3x^2-bx-6/x^2+3x+2 ( Please specify the equation if I'm wrong)
Step-by-step explanation:
ax^3+3x^2-x^2-bx-3x-6-2
=ax^3+2x^2-x(b+3)-8
Answer:
½
Step-by-step explanation:
Draw a picture of the triangle with the rectangle inside it.
Let's say the width and height of the triangle are w and h (these are constants).
Let's say the width and height of the rectangle are x and y (these are variables).
The area of the triangle is ½ wh.
The area of the rectangle is xy.
Using similar triangles, we can say:
(h − y) / h = x / w
x = (w/h) (h − y)
So the rectangle's area in terms of only y is:
A = (w/h) (h − y) y
A = (w/h) (hy − y²)
We want to maximize this, so find dA/dy and set to 0:
dA/dy = (w/h) (h − 2y)
0 = (w/h) (h − 2y)
0 = h − 2y
y = h/2
So the width of the rectangle is:
x = (w/h) (h − y)
x = (w/h) (h − h/2)
x = (w/h) (h/2)
x = w/2
That means the area of the rectangle is:
A = xy
A = ¼ wh
The ratio between the rectangle's area and the triangle's area is:
(¼ wh) / (½ wh)
½
So no matter what the dimensions of the triangle are, the maximum rectangle will always be ½ its area.
A function is a special relationship where each input has a single output.
therefore :
A is not a function; x=0; ⇒y₁=3; y₂=4
C is not a function; x=2;⇒ y₁=1; y₂=8
D is not a function; x=1;⇒y₁=2, y₂=-3
only B is a function; each input has a single output.