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3 years ago

9 students volunteer for a committee. How many different 2-person committees can be chosen?

Mathematics

1 answer:

jeka943 years ago

7 0

(7x6x5)/(1x2x3)=35. 35 groups :)

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Find the mode of the data.

mixer [17]

The mode is a term that is repeated the most.
And the one which is the repeated is 30.

6 0

3 years ago

Consider the figure. Determine the value of y.

slava [35]

Answer:

47+ y = 180 (linear pair)

y = 133

6 0

2 years ago

In the following table of values, the first differences are

ExtremeBDS [4]

Answer:

-7

Step-by-step explanation:

Given

$\begin{array}{ccc}x & {y} & {First\ difference} & {-2} & {34} & {}&{-1} & {27} & {} &{0} & {20} & {} & {1} & {13} & {} & {2} & {6} &{} \ \end{array}$

Required

The first difference

To do this, we simply calculate the difference between the consecutive y-values.

i.e.

$d = y_{n+1} - y_n$

So, we have:

$d = y_2 - y_1 = 27 - 34 = -7$

$d = y_3 - y_2 = 20 - 27 = -7$

$d = y_4 - y_3 = 13 - 20 = -7$

$d = y_5 - y_4 = 6-13 = -7$

<em>Hence, the first differences are -7 (all through)</em>

5 0

3 years ago

What is the mathematical relationship between the atomic radius (r) and the lattice parameter (a0) in the BCC structure? a. b. c

ryzh [129]

Answer: Lattice parameter, a = (4R)/(√3)

Step-by-step explanation:

The typical arrangement of atoms in a unit cell of BCC is shown in the first attachment.

The second attachment shows how to obtain the value of the diagonal of the base of the unit cell.

If the diagonal of the base of the unit cell = x

(a^2) + (a^2) = (x^2)

x = a(√2)

Then, diagonal across the unit cell (a cube) makes a right angled triangle with one side of the unit cell & the diagonal on the base of the unit cell.

Let the diagonal across the cube be y

Pythagoras theorem,

(a^2) + ((a(√2))^2) = (y^2)

(a^2) + 2(a^2) = (y^2) = 3(a^2)

y = a√3

But the diagonal through the cube = 4R (evident from the image in the first attachment)

y = 4R = a√3

a = (4R)/(√3)

QED!!!