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Snowcat [4.5K]
3 years ago
7

A certain forest covers an area of 2900 km. Suppose that each year this area decreases by 8.5%. What will the area be after 8 ye

ars?
Use the calculator provided and round your answer to the nearest square kilometer.
Mathematics
2 answers:
Daniel [21]3 years ago
4 0
The guy above is right :)
Ann [662]3 years ago
3 0

Answer:

1425 square kilometer.

Step-by-step explanation:

2900 - 8.5% = 2653.5

2653.5 - 8.5% = 2427.9525

2427.9525 - 8.5% = 2221.5765375

2221.5765375 - 8.5% = 2032.74253181

2032.74253181 - 8.5% = 1859.95941661

1859.95941661 - 8.5% = 1701.8628662

1701.8628662 - 8.5% = 1557.20452257

1557.20452257 - 8.5% =1 424.84213815 ≈ 1425

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The Xbox X is back in stock just in time for black Friday. Retailers are now offering the Xbox one S for 40% of the original pri
oksian1 [2.3K]

Answer:

230$ discount

Step-by-step explanation:

It costs 345$ now with a game pass

HOPE THIS HELPS

PLZZ MARK BRAINLIEST

6 0
3 years ago
The volume of a cube shaped shipping container is 2744 in.³ find the edge length of the shipping container
Dima020 [189]

Answer:

The edge length of the shipping container is 14 in.

Step-by-step explanation:

The volume enclosed by a cube  is the number of cubic units that will exactly fill a cube.

To find the volume of a cube  we need to recall that a cube has all edges the same length. The volume of a cube is found by multiplying the length of any edge by itself twice. Or as a formula:

                                                        V=s^3

where,  <em>s</em> is the length of any edge of the cube.  

To find the edge length of the shipping container we use the fact that the volume of a cube shaped shipping container is 2744 in³ and the above formula.

2744=s^3\\\\s^3=2744\\\\s=\sqrt[3]{2744}\\\\s = 14\:in

7 0
3 years ago
A tuna can weighs eighty-five grams. What is the weight of eleven tuna cans?
Anika [276]

Answer:

85g*11=935g

Step-by-step explanation:

1 tuna can = 85g

11 tuna cans is= 1*11

so 85g*11

3 0
2 years ago
Read 2 more answers
Here is a picture of an older version of the flag of Great Britain. There is a rigid transformation that takes Triangle 1 to Tri
Ainat [17]

Answer:

  The side lengths are the same.

Step-by-step explanation:

A rigid transformation does not change any dimensions. The side lengths are the same.

8 0
3 years ago
Read 2 more answers
Front housing for cell phones are manufactured in an injection molding process. The time the part is allowed to cool in the mold
astra-53 [7]

Answer:

Step-by-step explanation:

Hello!

The manufacturer suspects that the time a part for cell phones is allowed to cool in the mold influences the occurrence of a defect in the finished housing.

The claim is that the longer the part is left to cool down, the fewer defects appear.

To test this claim, two random samples of 20 parts each were taken, one was left to cool down 10sec and the other was left to cool down for 20sec. After the cooling time, each one was visually inspected and scored based on their appearance from 1 (lowest) to 10 (highest).

Resulting:

X₁: Score given to a manufactured part after a cooling time of 10 seconds.

n₁= 20 parts

X[bar]₁= 3.35

S₁= 2.01

X₂: Score given to a manufactured part after a cooling time of 20 seconds.

n₂= 20 parts

X[bar]₂= 6.50

S₂= 1.54

Assuming both variables have a normal distribution, and the population variances are equal, the statistic to use is a student t for two independent samples with pooled sample standard deviation.

If the longer the cooling time, the fewer defects appear in the part, then the mean score will be greater for the sample with higher cooling time.

The statistical hypotheses are:

H₀: μ₁ ≥ μ₂

H₁: μ₁ < μ₂

α: 0.05

t_{H_0}= \frac{((X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_1} } } ~~t_{n_1+n_2-2}

Sa^2= \frac{(n_1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2}

Sa^2= \frac{19*4.04+19*2.37}{20+20-2} = 3.81

Sa= 1.95

t_{H_0}= \frac{(3.35-6.50)-0}{1.95\sqrt{\frac{1}{20} +\frac{1}{20} } } = -5.108

This test is one tailed to the left and so is the p-value, you can reach the value as follow:

p-value: P(t_{38}\leq -5.108) ≅ 0.00001

p-value < 0.00001

The p.value is less than the significance level, the decision is to reject the null hypothesis.

Using a level of significance of 5% there is enough statistical evidence to reject the null hypothesis, so you can say that the average inspection scores of the parts that cooled down for 10 seconds are less than the average inspections scores of the parts that cooled down for 20 seconds, which means that the longer the cooling time, the fewer defects appear in the cellphone housing.

*-*-*

95% CI for the difference of means μ₁ - μ₂

The formula for the confidence interval is:

[(X[bar]₁-X[bar]₂) ± t_{n_1+n_2-2;1-\alpha /2} * (Sa \sqrt{\frac{1}{n_1} +\frac{1}{n_2} } )]

t_{n_1+n_2-2;1-\alpha /2} = t_{38;0.975}= 2.024

[(3.35-6.50)±2.024*(1.95*\sqrt{\frac{1}{20} +\frac{1}{20} })]

[-4.40;-1.90]

With a confidence level of 95%, you'd expect that the true value of the difference between the inspection scores of the parts that cooled down for 10 seconds and inspections scores of the parts that cooled down for 20 seconds will be included in the interval [-4.40;-1.90].

I hope it helps!

3 0
3 years ago
Read 2 more answers
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