Triangle ABC has vertices at A(-3, 5), B(0, 0), and C(6, 5). It is transformed so that Triangle A'B'C' has coordinates A'(1, 11)
1 answer:
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Y = 3x + 1
Because,
slope intercept form is y=mx+b
Where y is the y values, m is slope, x is x values, and b is y-intercept
First, to find the slope use rise/run, so rise (from 10 to 13) is 3 and run is (from 3 to 4) is 1, 3/1=3
Next to find y-intercept plug in the slope and some x and y values,
10=3(3)+b
10=9+b
1=b
So then the equation is y=3x+1 you can check by plugging stuff in and also I graphed it so I’ll add a picture
This is my first time answering questions so if I got something wrong ask or something hope this helps :)
Because,
slope intercept form is y=mx+b
Where y is the y values, m is slope, x is x values, and b is y-intercept
First, to find the slope use rise/run, so rise (from 10 to 13) is 3 and run is (from 3 to 4) is 1, 3/1=3
Next to find y-intercept plug in the slope and some x and y values,
10=3(3)+b
10=9+b
1=b
So then the equation is y=3x+1 you can check by plugging stuff in and also I graphed it so I’ll add a picture
This is my first time answering questions so if I got something wrong ask or something hope this helps :)
Answer:
m = - 1
Step-by-step explanation:
Given
= - 6
Multiply both sides by 2 to clear the fraction
15m + 3 = - 12 ( subtract 3 from both sides )
15m = - 15 ( divide both sides by 15 )
m = - 1