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djverab [1.8K]
3 years ago
7

Max is thinking of a number, which he calls n. He adds 8 an then doubles the sum

Mathematics
2 answers:
polet [3.4K]3 years ago
6 0

Answer:n+16

Step-by-step explanation:n+8×2

LenKa [72]3 years ago
4 0

decimal:

3.2

fraction:

3.2/1

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iren2701 [21]

Answer:

so, it's 0.1x35=3.5

it will be lowered by 3.5 dollars

5 0
3 years ago
Read 2 more answers
What Does X Equal In This Algebraic Expression
lilavasa [31]
Thank you for your question!

Your really close!
Just set this up as an algebraic equation:
4x - 10 = 30
4x = 40
x = 10

Hope this helped!
8 0
4 years ago
A student used the equation below to create a table. y = –3x – 5 The student used –2 as one of the values for the input. Which o
Angelina_Jolie [31]

The ordered pair that could be taken from the table is: C. (–2, 1).

<h3>Ordered pairs of a Table</h3>

Ordered pairs are given as, (x, y). To find either x or y of a pair given an equation, plug in the given given to find the corresponding missing value of the ordered pair.

Input value = x-values, while output value = y-values.

Given:

y = –3x – 5

Let's find the corresponding y-value (output) of x = -2.

Substitute x = -2 into y = –3x – 5.

y = –3(-2) – 5

y = 6 - 5

y = 1

Therefore, the ordered pair that could be taken from the table is: C. (–2, 1).

Learn more about ordered pairs on:

brainly.com/question/1528681

7 0
3 years ago
True or false? -4 is a natural number.
Vika [28.1K]
No, -4 is not a natural number. It is a negative, the only natural numbers are positiv numbers. Hope this helped!
4 0
4 years ago
25x^-4-99x^-2-4=0 <br> How do I solve for this?
OlgaM077 [116]

Given

25x^{-4} - 99x^{-2} - 4 = 0

consider substituting y=x^{-2} to get a proper quadratic equation,

25y^2 - 99y - 4 = 0

Solve for y ; we can factorize to get

(25y + 1) (y - 4) = 0

25y+1 = 0 \text{ or } y - 4 = 0

y = -\dfrac1{25} \text{ or }y = 4

Solve for x :

x^{-2} = -\dfrac1{25} \text{ or }x^{-2} = 4

The first equation has no real solution, since x^{-2} = \frac1{x^2} > 0 for all non-zero x. Proceeding with the second equation, we get

x^{-2} = 4 \implies x^2 = \dfrac14 \implies x = \pm\sqrt{\dfrac14} = \boxed{\pm \dfrac12}

If we want to find all complex solutions, we take i=\sqrt{-1} so that the first equation above would have led us to

x^{-2} = -\dfrac1{25} \implies x^2 = -25 \implies x = \pm\sqrt{-25} = \pm5i

8 0
2 years ago
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