The owners added a second floor to the house. The second floor is 50 feet long and 30 feet wide with ceilings that are 9 feet ta
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The dimensions of the rectangle are length 156 m and a width of 65m, and a perimeter P = 442m
<h3>How to find the dimensions of the rectangle?</h3>For a rectangle of length L and width W, the diagonal is:
Here we know that the diagonal is 169m.
And the ratio of the length to the width is 12:5
This means that:
W = (5/12)*L
Replacing all that in the diagonal equation:
So the length is 156 meters, and the width is:
W = (5/12)*156 m = 65m
Finally, the perimeter is:
P = 2*(L + W) = 2*(156 m + 65m) = 442m
If you want to learn more about rectangles:
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Answer:
Step-by-step explanation:
The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9
To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.
= (1 / determinant of A) x Adjoint of A
the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2
Adjoint of A =
=
=