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Dovator [93]
2 years ago
7

What percent of 80 is 200?

Mathematics
2 answers:
mario62 [17]2 years ago
4 0

Answer:

80 is 40% percent of 200

but 200 is 140 percent of 80

Step-by-step explanation:


laiz [17]2 years ago
4 0

Hello there! Your answer is 160 percent.

To solve, set up a system of equations that models your situation:

\frac{200}{100} = \frac{x}{80}

Now, cross multiply.

100x = 200(80)

100x = 16000

x = 160

So, 200 is 160 percent of 80.

I hope this helps and have a great day! :)

<em>Please let me know if you need any further help with </em><em>this</em><em> question.</em>

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6 0
2 years ago
Find the value of x in the equation x⁄ 4 + x⁄14 + x⁄17 = 71
Morgarella [4.7K]

Hello from MrBillDoesMath!

Answer:

33769/181

Discussion:

Each term contains "x" so factoring it out gives

x( 1/4 + 1/14 + 1/17)  = 71       (*)

Use common factor (17*14*4  = 952) as the denominator to combine terms:

1/4 =  (17*14)/ 952  = 238/952

1/14 = (17*4)/952 = 68/952

1/17 = (14*4)/952  = 56/952

so 1/4 + 1/14 + 1/17 =    (238 + 68 + 56)/ 952 =  362/952 = 181/476

Substituting in (*) gives

x ( 181/476)  = 71                       => multiply both sides by 476/181

x = (71 * 476)/181                       => 71* 476 =33769

x = 33769/181

Thank you,

MrB

4 0
3 years ago
A church rings its bells every 15 minutes, the school rings its bells every 20 minutes and the day care center rings its bells e
ankoles [38]

Answer:

As few as just over 345 minutes (23×15) or as many as just under 375 minutes (25×15).

Imagine a simpler problem: the bell has rung just two times since Ms. Johnson went into her office. How long has Ms. Johnson been in her office? It could be almost as short as just 15 minutes (1×15), if Ms. Johnson went into her office just before the bell rang the first time, and the bell has just rung again for the second time.

Or it could be almost as long as 45 minutes (3×15), if Ms. Johnson went into her office just after the bells rang, and then 15 minutes later the bells rang for the first time, and then 15 minutes after that the bells rang for the second time, and now it’s been 15 minutes after that.

So if the bells have run two times since Ms. Johnson went into her office, she could have been there between 15 minutes and 45 minutes. The same logic applies to the case where the bells have rung 24 times—it could have been any duration between 345 and 375 minutes since the moment we started paying attention to the bells!

Step-by-step explanation:

7 0
3 years ago
Suppose you have 18 objects (10 of type A, 5 of type B, and 3 of type C). Objects of type A are indistinguishable from each othe
Paladinen [302]

Answer:

\binom{18}{5}= 8568

Step-by-step explanation:

Note that we have in total 18 items. Even though we are given information regarding the amounts of items per type, the general question asks the total number of ways in which you can pick 5 out of the 18 objects, without any restriction on the type of chosen items. Therefore, the information regarding the type is unnecessary to solve the problem.

Recall that given n elements, the different ways of choosing k elements out of n is given by the binomial coefficient \binom{n}{k}).

Therefore, in this case the total number of ways is just \binom{18}{5}=8568

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3 years ago
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Step-by-step explanation:

A. a numerical expression I am pretty sure

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