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2 years ago

Covert 9.46×^10-6 into regular notation

Mathematics

1 answer:

weqwewe [10]2 years ago

5 0

Answer:

0.00000946

Step-by-step explanation:

9.46×^10⁻⁶ =0.00000946

<u>Trick:</u>

Since the exponent of the scientific notation is negative, move the decimal point 6 places to the left

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Read 2 more answers

Solve for x in the equation X2-8x+41 = 0 -

djverab [1.8K]

Answer:

The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D

Step-by-step explanation:

Given equation as :

x² - 8 x + 41 = 0

For quadratic equation ax² + b x + c = 0

The value of x = $\frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

∴ For equation x² - 8 x + 41 = 0

Or, x = $\frac{8\pm \sqrt{-8^{2}-4\times 1\times 41}}{2\times 1}$

Or, x = $\frac{8\pm \sqrt{-100}}{2}$

Or, x = $\frac{8\pm 10i}{2}$

∴ x = ( 4 + 2 i ) , ( 4 - 2 i )

Hence The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D Answer

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3 years ago

PLEASEEEEEE HELPPPPPPPP

Natali5045456 [20]

The formula for the sum of n terms in an arithmetic progression is:
S = n/2 * (2a + (n-1)d)
Here, the common difference, d, is 8 and the first term, a, is 1. Substituting these into the formula, we get:

S = n/2 * (2*1 + 8(n - 1))
S = n + 4n² - 4n
S = 4n² - 3n
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2 years ago

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Step-by-step explanation:

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