Answer:
306.8 feet
Step-by-step explanation:
Refer the attached figure .
A surveyor moves 160 feet away from the base of the pole i.e. ED = 160 m
Referring the image .
AC=ED=160 m
A transit i.e. AE is 6 feet tall.
AE = CD=6 feet
With a transmit the angle of elevation to the top of the pole to be 62° i.e. ∠BAC = 62°
To Find BC , use tigonometric ratio.
Now, the height of the pole = BC+CD =300.8+6=306.8 feet
Hence the height of the pole is 306.8 feet
I guess you mean 'each'.
They could be:-
_
2 , 1/2 and 0.3
The markings indicate the figures are congruent. The orientation of both figures is clockwise, so no reflection is involved. The direction of QR appears to be 90° counterclockwise from the direction of EF, It appears as though the center of rotation is somewhere in the triangle EGS.
The transformation appears to be a 90° CCW rotation.
If the clinic "assumes" property taxes, it should mean the property taxes were for a past period, so it counts as part of the cost. If the property taxes are for a period after the transaction, it does not count as part of the cost. Finally if property taxes straddle the transaction date, the prorated part prior to that date counts as cost.
Title and attorney fees can count as cost.
Grading the land is what he decides to do after the transaction, so does not count as cost. If this was a condition for the transaction, the previous owner should have paid for it.
Hope everything is clear.
Answer: knm = 131
Step-by-step explanation:
