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SpyIntel [72]
3 years ago
6

Hey can you please help me posted picture of question

Mathematics
2 answers:
Mariana [72]3 years ago
8 0
The answer to the question is b
Anni [7]3 years ago
6 0
You multiply the options in each section:

Shirts x skirts x shoes
7 x 6 x 4
=168

So, there are 168 combinations- Letter answer B
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Graph 2x+3y=1,470. On the graph, make sure to label the intercepts. You may graph your equation by hand on a piece of paper and
Yuki888 [10]

Answer:

  • x-intercept: 735
  • y-intercept: 490

Step-by-step explanation:

See the attachment for a graph.

4 0
3 years ago
The expression 2a+1.5b 2a+1.5b  gives the cost (in dollars) for a a cupcakes and b b cookies at a bake sale
zepelin [54]
Is there a question here? I can't see it!
5 0
3 years ago
Please help solve for x..
aalyn [17]

Answer:

x = 1 or x = -1

Step-by-step explanation:

Given equation:

x^{100}-4^x \cdot x^{98}-x^2+4^x=0

Factor out -1:

\implies -1(-x^{100}+4^x \cdot x^{98}+x^2-4^x)=0

Divide both sides by -1:

\implies -x^{100}+4^x \cdot x^{98}+x^2-4^x=0

Rearrange the terms:

\implies 4^x \cdot x^{98}-4^x-x^{100}+x^2=0

\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c \quad \textsf{to }x^{100}:

\implies 4^x \cdot x^{98}-4^x-x^{98}x^2+x^2=0

Factor the first two terms and the last two terms separately:

\implies 4^x(x^{98}-1)-x^2(x^{98}-1)=0

Factor out the common term (x^{98}-1) :

\implies (4^x-x^2)(x^{98}-1)=0

<u>Zero Product Property</u>:  If a ⋅ b = 0 then either a = 0 or b = 0 (or both).

Using the <u>Zero Product Property</u>, set each factor equal to zero and solve for x (if possible):

\begin{aligned}x^{98}-1 & = 0 & \quad \textsf{or} \quad \quad4^x-x^2 & = 0 \\x^{98} & =1 & 4^x & = x^2 \\x & = 1, -1 & \textsf{no}& \textsf{ solutions for } x \in \mathbb{R}\end{aligned}

Therefore, the solutions to the given equation are: x = 1 or x = -1

Learn more here:

brainly.com/question/27751281

brainly.com/question/21186424

3 0
1 year ago
Prove x²+y² = (x+y) (x-y)​
gtnhenbr [62]

Answer:

(x+y)(x-y)

x^2 - xy + xy - y^2

x^2 - y^2

7 0
2 years ago
What can we use to measure liquid and solid
Mrac [35]

Answer: measuring cups??

Step-by-step explanation:

5 0
3 years ago
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