3 years ago

I need help ASAP!!!!!

1 answer:

3 0

If we know that two sets of corresponding angles and the corresponding included sides are congruent in two triangles, what can we say about the triangles?

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E^4x-5-e=0 Solve the equation for x

kati45 [8]

Answer:

$x = \frac{1}{4} \times In(5 + e)$

Step-by-step explanation:

${e}^{4x} - 5 - e = 0 \\ {e}^{4x} = 5 + e \\ 4x = In(5 + e) \\$

$\boxed{Answer:{\boxed{\green{x = \frac{1}{4} \times In(5 + e)}}}}$

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3 years ago

A cone is placed inside a cylinder as shown. The radius of the cone is half the radius of the cylinder. The height of the cone i

kondaur [170]

Given:
Volume of the cone = π r² h/3

radius of the cone is half the radius of the cylinder ⇒ r/2
height of the cone is equal to the radius of the cylinder. ⇒ r

V = 3.14 * (r/2)² * r/3
V = 3.14 * r²/4 * r/3
V = 3.14r³ / 12

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3 years ago

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darren jogs 425 meters and runs 650 meters in one workout.he performs this workout three times .what is the total distance cover

Igoryamba

425+650=1075 1075x3=3225

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4 years ago

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Cal's go cart has a gas tank with the dimensions shown below.

In-s [12.5K]

Answer: 2 cans.

Step-by-step explanation:

Calculate the volume of the go cart tank, which has the form of a rectangular prism. You can use the following formula:

$V=l*w*h$

Where:

l: is the lenght.

w: is the width.

h: is the height.

In this case:

$l=15.4in\\w=10in\\h=3in$

Substitute values into the formula. Then:

$V=(15.4in)(10in)(3in)=462in^3$

If a gas can holds 1 gallon of gas and $1\ gallon=231\ in^3$ , then the number of full gas cans that will take to fill the go cart's tank (whose volume is 462 in³) is:

$gas\ cans=\frac{(462in^3)(1can)}{(231in^3)}=2\ cans$

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3 years ago

Item has been reduced by 80% what is the price of the item now?

Eva8 [605]

I think you use

xamount(1-.8)

.8 being 80% as a decimal.

1 being 100%

so .2 or 20% remaining multiplied by whatever amount.

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4 years ago