I am assuming from What I have found is that a is the base , b is angle between a and x and x is the hypotenuse .
So we know that
cos θ =base/hypotenuse
here θ = 3π/8 =67.5 degree
cos 67.5 =0.38268
so
0.38268=a/x
x=25/0.38268
x=65.32873
Answer:
s = 4
Step-by-step explanation:
3r = 10 + 5s
3×10 = 10 + 5s
5s = 30 - 10
5s = 20
s = 20 : 5
s = 4
Solution:
The given equation is:
A: Taking , x=1
L H S = 9 × 1 + 49 = 9 + 49= 58
R H S : 
L H S ≠ R H S
B: Taking x=3
L H S = 9 × 3 + 49=27 + 49=76
R HS = 
L H S ≠ R H S
C: Taking x=5
L H S = 9 × 5 + 49
= 45 + 49
= 94
R H S:
L H S ≠ R H S
(D)
when , x= 8
L H S
9 × 8 + 49
= 72 + 49
= 121
R HS:
L H S ≠ R H S
So you do 93 times 60 because it said you have to do 6 ten times and that equal 5580
Here,
y=mx+c
the slope of the line 6x+4y= -16 is -20.
if the two lines are perpendicular, the slope of 1st line * slope of second line=-1
the slope of the 2nd line is -1/2
y-y1=m(x-x1)
y-13=-1/2(x- -18)
when you solve, you get the equation of the line as 2y+x=50
In basic geometry, if two geometry objects intersect at right angles (90 degrees or π / 2 radians), they are vertical.
If two lines intersect at right angles, the line is perpendicular to another line. Explicitly (1) if two lines intersect, the first line is perpendicular to the second line. (2) At the intersection, the straight line angle on one side of the first line is cut by the second line into two congruent angles. Verticality can be shown as symmetric. That is, if the first line is perpendicular to the second line, then the second line is also perpendicular to the first line. Therefore, two straight lines can be said to be perpendicular (to each other) without specifying the order.
Learn more about Perpendicular here: brainly.com/question/7098341
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