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Flauer [41]
4 years ago
10

Complete the table below to solve the equation 2.5x − 10.5 = 64(0.5x).1. Be careful when putting exponents into your calculator-

do then first and then the rest of the equation!
f(x) = 2.5x − 10.5



g(x)=64(0.5^x)
16
Mathematics
1 answer:
ololo11 [35]4 years ago
3 0
The answer would be a simple 5 time itselsf
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A Turtle and a Snail are 360 meters apart, and they start to move towards each other at 3 p.m. If the Turtle is 11 times as fast
Arisa [49]
We have to deal with the distance in more detail
If the turtle is 11 times faster than the snail, the amount of distance he will cover is 11 times more.
d/(360 - d) = 1/11
11d = 360 - d
12d = 360
d =  30  The Snail covers 30 meters. The turtle covers 11*30 = 330 meters.

Answers
Rate of snail = 30 meters / 40 minutes = 3/4 meter / minute
Rate of turtle = 330 meters / 40 minutes = 8.25 meters / minute.
6 0
3 years ago
Help please!!!!!!!!!!
adell [148]

Answer:

1/2?

Step-by-step explanation:

8 0
3 years ago
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What are the zeros of the function: f(x) = 2x^2-50
yan [13]
When f(x) = 0, 

2x^2 - 50 = 0

2(x^2 - 25) = 0

2(x- 5)(x + 5) = 0

(x - 5) = 0 \ or  \ (x + 5) = 0

x = 5 \ or \ x = -5

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Answer : x = 5 or -5
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3 0
4 years ago
Read 2 more answers
⅔ (5/16)=equal too ??
Zepler [3.9K]

This is the answer

.... <em>please</em><em> mark</em><em> brainliest</em>

5 0
3 years ago
X-4[x-2(x+6)]=5x+3<br><img src="https://tex.z-dn.net/?f=x%20-%204%20%20%20%5B%20%20x%20-%202%28x%20%2B%206%29%5D%20%20%3D%205x%2
pshichka [43]

The equivalence of the equation is 5x + 48 = 5x + 3.

Since 48 cannot be equal to 3, hence there are no solution.

<h3>What is the value of x?</h3>

Given the equation; x-4[ x - 2( x + 6) ] = 5x + 3

We remove the parentheses

x-4[ x - 2( x + 6) ] = 5x + 3

x-4[ x - 2x - 12 ] = 5x + 3

x - 4x + 8x + 48 = 5x + 3

5x + 48 = 5x + 3

We can go further and collect like terms

5x - 5x + 48 = 3

48 ≠ 3

Since 48 cannot be equal to 3, hence there are no solution.

Learn more about equations here: brainly.com/question/14686792

#SPJ1

7 0
2 years ago
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