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3 years ago

IM SICK OF ALL THE FAKE LINKS! Can I get help?

Mathematics

1 answer:

Virty [35]3 years ago

5 0

Answer:

equation: 28 = 2h+ h + h or you could say 28 = 4h

h= 7

Step-by-step explanation:

since both lines are the same length they equal each other.

to get h = 7 you have to solve the equation you made.

28 = 4h

28/4 = 4h/4

7 = h

mark as brainliest please :)

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GCF of 8x^8 and 28x^4

hichkok12 [17]

8x^8=2*2*2*x*x*x*x*x*x*x*x
28x^4=2*2*7*x*x*x*x

GCF is the common group
GCF=2*2*x*x*x*x
GCF=4x^4

8 0

4 years ago

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tatyana61 [14]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Solve for t. d= -16t^2 + 12

IRINA_888 [86]

Answer:

t=√d-12/4 and t=√-d-12/4, d≥12

Step-by-step explanation:

Hope this helps.

3 0

3 years ago

the frame of a picture is 28 cm by 32 cm outside and is of uniform width.What is the width of the frame if 192 cm2 of the pictur

natita [175]

Answer:

The width of the frame is equal to $8\ cm$

Step-by-step explanation:

Let

x-------> the width of the frame picture

we know that

$(28-2x)(32-2x)=192$

$896-56x-64x+4x^{2} =192$

$4x^{2}-120x+704=0$

Simplify

$x^{2}-30x+176=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-30x+176=0$

$a=1\\b=-30\\c=176$

substitute in the formula

$x=\frac{30(+/-)\sqrt{(-30)^{2}-4(1)(176)}} {2(1)}$

$x=\frac{30(+/-)\sqrt{196}} {2}$

$x=\frac{30(+/-)14} {2}$

$x=\frac{30+14} {2}=22\ cm$ ----> this solution is not logic

$x=\frac{30-14} {2}=8\ cm$

The width of the frame is equal to $8\ cm$

8 0

4 years ago

2+2 help please I will give brainliest

liberstina [14]

The answer is 4 isn’t it?

3 0

3 years ago