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Mademuasel [1]
3 years ago
8

IM SICK OF ALL THE FAKE LINKS! Can I get help?

Mathematics
1 answer:
Virty [35]3 years ago
5 0

Answer:

equation: 28 = 2h+ h + h or you could say 28 = 4h

h= 7

Step-by-step explanation:

since both lines are the same length they equal each other.

to get h = 7 you have to solve the equation you made.

28 = 4h

28/4 = 4h/4

7 = h

mark as brainliest please :)

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Help
zalisa [80]
<h2>♪Answer : </h2>

Ingat rumus determinan fungsi kuadrat yaitu :

\longmapsto\boxed{\sf{D = b^2 - 4ac}}

Maka, Kita kembali jawab soalnya.

⏩Nomor (1) :

»8x² + 7x + 10 = 0

Didapatkan nilai² a, b, dan c yaitu :

  • a = 8 | b = 7 | c = 10

Maka, nilai determinannya adalah

  • D = b² - 4ac
  • D = 7² - 4(8)(10)
  • D = 49 - 4(80)
  • D = 49 - 320
  • D = -271✅

\:

⏩Nomor (2) ;

»2x² + 10x + 10 = 5

»2x² + 10x + 10 - 5 = 0

»2x² + 10x + 5 = 0

Didapatkan nilai² a, b, dan c yaitu :

  • a = 2 | b = 10 | c = 5

Maka, nilai determinannya adalah

  • D = b² - 4ac
  • D = 10² - 4(2)(5)
  • D = 100 - 4(10)
  • D = 100 - 40
  • D = 60✅
6 0
2 years ago
Read 2 more answers
Kendra is considering two different long-distance phone plans. Phone plan A charges a $100 sign-up fee and 3 cents per minute. P
Fed [463]

Answer:

Part 1) The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2) The number of minutes in a month must be equal to 50 minutes

Step-by-step explanation:

<u><em>The question is</em></u>

Part 1) How many minutes would Kendra have to use in a month in order for the plan A to be preferable? Round your answer to the nearest minute

Part 2) Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan

Part 1)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A to be cheaper than plan B, the following inequality must hold true.

cost of plan A < cost of plan B

substitute

3x+100 < 5x

solve for x

subtract 3x both sides

100< 5x-3x\\100

divide by 2 both sides

50 < x

Rewrite

x> 50\ min

therefore

The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A cost the same than plan B, the following equation must hold true.

cost of plan A = cost of plan B

substitute

3x+100= 5x

solve for x

5x-3x=100\\2x=100\\x=50\ min

therefore

The number of minutes in a month must be equal to 50 minutes

5 0
3 years ago
Name the algebraic property demonstrated in the example below: If x = 3 and 3 = y, then x = y.
NemiM [27]
Its the transitive property. Transitive means that is a=b and b=c then a=c. It matches with what they're asking for. 
8 0
3 years ago
Find the mean absolute deviation for the set {-32, 9, 11, 12}
Zolol [24]
<h3>Answer:</h3>

A

Step-by-step explanation:

{-32, 9, 11, 12}

first, find the mean (Find the sum of the data values, and divide the sum by the number of data values )

(-32) + 9 + 11 + 12 = 0

0/0 = 0

then, find the absolute value of the difference between each data value and the mean: |data value – mean|.

-32 - 0= -32

9 -0 = 9

11 -0 = 11

12 -0 = 0

finally, find the sum of the absolute values of the differences. Divide the sum of the absolute values of the differences by the number of data values.

0 - 0 / 4 = 0

answer is 0 (A)

7 0
4 years ago
Chris wants to put six plants in a row on his windowsill. He randomly chooses each plant to be an aloe plant, a basil plant, or
babunello [35]
Probability is the study of calculating the chances or likelihood of an event occurring out of the total number of events. This likelihood is always presented as part of a whole. It could be in fractions or percentages.

There are two techniques to apply to this problem. First, we use the repeated trial equation:

P = n!/r!(n-r)! * p^(n-r) * q^r

This is used to determine the probability that an event will occur exactly 'r' times out of 'n' trials. p is the probability of success, while q is the probability of failure. Together, they add up to 1. In this case, each kind of plant has 1/3 probability. So, p=1/3 and q=2/3.

Second thing to note when dealing with probability problems are 'hint words'. When you are asked to find the probability of event A 'AND' event B happening, then you multiply their probabilities. However, when you are asked to find the probability of event A 'OR' event B happening, then you add their probabilities. Hence, the solution to this problem is:

P = 6!/4!(6-4)! * (1/3)^6-4 * (2/3)^4    +    6!/5!(6-5)! * (1/3)^6-5 * (2/3)^5
P = 0.596 or 59.6%
3 0
3 years ago
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