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oee [108]
3 years ago
15

For Halloween, Isabel received 5 6/7 pounds of candy in the first hour and another 3 4/9 pounds the second hour. How much candy

did she get total?
Mathematics
2 answers:
katen-ka-za [31]3 years ago
8 0

Answer:

64/9 or 7 or 1/9

Step-by-step explanation:

4 3/9 + 2 7/9 = 64

9

= 71

9

liraira [26]3 years ago
4 0

Answer:

HINT NOT TELL

Step-by-step explanation:

5 + 3 = 8

then you can do the rest.

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Find the value of n in 2m-3n = 6 and 2m + 6n = 12.​
Nezavi [6.7K]

Answer:

n = 2/3

Step-by-step explanation:

2m - 3n = 6

– 2m + 6n = 12

<u>____-____-___</u>

-9n = -6

n = -6/-9

n = 2/3

Hence, the value of n in the given equations is 2/3.

4 0
2 years ago
Question in picture solve
dimulka [17.4K]

Answer:

x= 13.5

Step-by-step explanation:

f(x) = 2x + 9

f(x) = 36

Set the 2 equations equal to each other;

2x + 9 = 36

Subtract 9 from both sides;

2x = 27

Divide both sides by 2;

x = 13.5

<em>Check:</em>

f(x) = 2x + 9

f(13.5) = 2(13.5) + 9= 27 + 9 = 36

3 0
3 years ago
The square below represents one whole.
grandymaker [24]

Answer:

Fraction: 81/100

Decimal: 0.81

Percentage: 81%

Step-by-step explanation:

The question is complete but the diagram mentioned can be found in

brainly.com/question/12188410

First step is to find the area of the whole square and then the area of the part that was shaded.

From the diagram, there are 100 squares in the whole square. 81 of those squares are shaded.

Area of the whole square = 10 by 10

= 10×10 = 100unit²

Area of shaded region = (10 by 8) + 1

= 80+1 = 81unit²

shaded area expressed as a fraction = 81unit²/100unit²

= 81/100

Shaded area expressed as a decimal = 81/100

You take the number 81 and carry the point by two decimal place from the right

= 0.81

Shaded area expressed as a percent of the whole = (81/100) × 100

= (81×100)/100

= 81%

6 0
3 years ago
Tori has a bag with 3 blue marbles, 5 red marbles and 1 yellow marble. She chooses a marble at random, returns it to the bag, an
Damm [24]

Answer:

3-    5-   1

^      ^     ^

1 -5, 1,3   3,5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A ball is thrown from an initial height of 1 meter with an initial upward velocity of 15m/s. The ball's height h (in meters) aft
lakkis [162]

\bf \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{h}=1+15t-5t^2}\implies \stackrel{\textit{ball's height}~\hfill }{\stackrel{\downarrow }{6}=1+15t-5t^2}\implies 0=-5+15t-5t^2 \\\\\\ ~~~~~~~~~~~~\textit{using the quadratic formula} \\\\ \stackrel{\stackrel{a}{\downarrow }}{5}t^2\stackrel{\stackrel{b}{\downarrow }}{-15}t\stackrel{\stackrel{c}{\downarrow }}{+5}=0 \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}

\bf t=\cfrac{-(-15)\pm\sqrt{(-15)^2-4(5)(5)}}{2(5)}\implies t=\cfrac{15\pm\sqrt{225-100}}{10} \\\\\\ t=\cfrac{15\pm\sqrt{125}}{10}\implies t=\cfrac{15\pm\sqrt{5^2 \cdot 5}}{10}\implies t=\cfrac{\stackrel{3}{~~\begin{matrix} 15 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\pm ~~\begin{matrix} 5 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~\sqrt{5}}{\underset{2}{~~\begin{matrix} 10 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}

\bf t=\cfrac{3\pm \sqrt{5}}{2}\implies t= \begin{cases} \frac{3+ \sqrt{5}}{2} \approx 2.618\\\\ \frac{3- \sqrt{5}}{2}\approx 0.382 \end{cases}

8 0
3 years ago
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