Answer:
The second one is no
i done know the first one though give me a second to solve
Step-by-step explanation:
-52 is the answer because you have to isolate 1/3x by adding 2/3 to -18 then you have to multiply -18/1 by 3 so you can have a common denominator. After, you should have -54/3 plus 2/3 you subtract the two and get -52/3. You then have 1/3x equals -52/3. You divide 1/3x by -52/3 which means you have to multiply by the reciprocal of 1/3x which is 3/1x. You multiply that by -52/3. The threes cancel out and you're left with x = -52.
Answer:
c=-x^2+5x
Step-by-step explanation:
9514 1404 393
Answer:
- 22.0
- 15.0
- 30.0°
- 137.0°
Step-by-step explanation:
These are all Law of Cosine problems. A generic expression for the length of side 'c' opposite angle C, which is defined by sides 'a' and 'b' is ...
c² = a² +b² -2ab·cos(C)
The square root of this gives the side length:
c = √(a² +b² -2ab·cos(C))
Rearranging the equation, we can obtain an expression for the angle C.
C = arccos((a² +b² -c²)/(2ab))
These two formulas are used to solve the offered problems.
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1) AC = √(13² +14² -2·13·14·cos(109°)) ≈ √483.506
AC ≈ 22.0
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2) BC = √(7² +10² -2·7·10·cos(123°)) ≈ √225.249
BC ≈ 15.0
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3) ∠B = arccos((24² +28² -14²)/(2·24·28)) = arccos(1164/1344)
∠B ≈ 30.0°
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4) ∠B = arccos((6² +9² -14²)/(2·6·9)) = arccos(-79/108)
∠B ≈ 137.0°
Answer:
If two lines are parallel, then they have the same gradient.
Step-by-step explanation:
L is y=3x-2
L*2 is 3y-9x+5=0
The gradient for the first equation is 3
We need to rearrange the second equation and see if it has the same gradient as the first equation.
L*2 is 3y-9x+5=0
3y = 9x - 5
L*2 y = 3x - 5/3
As you can see, once you rearrange and simplify the equation, the second line has the same gradient as the first equation.
So that means these two lines are parallel
