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-BARSIC- [3]
3 years ago
11

An example of consecutive odd integers is 23, 25, 27, and 29. Find four consecutive odd integers with a sum of 160. Show your wo

rk. After completing the problem, write out the steps, in words, that you used to solve the problem??????????????? Please tell me the steps to so I can understand please.
Mathematics
1 answer:
Andrew [12]3 years ago
8 0
Step1: Define an odd integer.
Define the first odd integer as (2n + 1), for n = 0,1,2, ...,
Note that n is an integer that takes values 0,1,2, and so no.

Step 2: Create four consecutive odd integers.
Multiplying n by 2 guarantees that 2n will be zero or an even number.
Therefore (2n + 1) is guaranteed to be an odd number.
By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.

Let the four consecutive odd integers be
2n+1, 2n +3, 2n +5, 2n +7 

Step 3: require that the four consecutive integers sum to 160.
Because the sum of the four consecutive odd integers is 160, therefore
2n+1 + 2n+3 + 2n+5 + 2n +7 = 160
8n + 16 = 160
8n = 144
n = 18

Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.

Answer: 37,39,41,43

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If my paycheck was $1,417 and they take out 5% of that how much are they taking out​
docker41 [41]

Answer:

70.85

Step-by-step explanation:

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5/100*1417

6 0
3 years ago
How many constants can a polynomial have? Explain your answer
Katyanochek1 [597]
A polynomial can only have one constant, since the constant is the one number being added or subtracted from the rest of the polynomial, and it is the only number that is not being multiplied by an x value.
6 0
3 years ago
The range of F(x) = logbx is the set of all positive real numbers.
shtirl [24]

Answer:

The range of F(x) = logbx is the set of all positive real numbers is TRUE

Step-by-step explanation:

Given:

A function which logarithmic i.e F(x)=logbX=logx/logb  with base 10

To Find;

Range belongs to All set are positive real numbers.

Solution:

The domain is function for which all set of inputs are defined  and range for function is that set of all output that functions takes.

So Simple logarithmic function y=logbX is

X=b^y

So  The functions has domain of all real values  and range set of all real number.

In general the function F(x) = logbx  where X>0 and b≠1  is continuous and one to one function.

logarithmic function is not defined for negative numbers or for zero.

And Also function approaches y-axis as x-tends to infinity but never touches the it.

Hence the Given statement is true

7 0
4 years ago
Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.
Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)  

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

  • the points will be clustered according to their distance to the centroids.
  • Then centroids are updated as the cluster means.
  • This process continues until clusters doesn't change anymore

1)  <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24)  mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = (18-6)^{2}+(18-12)^{2}+(18-18)^{2}+(18-24)^{2}+(18-30)^{2}+(45-42)^{2}+(45-48)^{2}=378

2)<u><em>initial centroids</em></u> 10-20

first cluster (6,12)  mean:9

second cluster (18,24,30,42,48)  mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>final centroids</em></u> 15-40

first cluster (6,12,18,24) mean:15  

second cluster (30,42,48) mean:40

Sum of Squared errors = (15-6)^{2}+(15-12)^{2}+(15-18)^{2}+(15-24)^{2}+(40-30)^{2}+(40-42)^{2}+(40-48)^{2}=348

6 0
3 years ago
What is the mean of the data set?
olga nikolaevna [1]

Answer:

183

Step-by-step explanation:

125+141+213+155+281=915

915 divided by 5=183


3 0
4 years ago
Read 2 more answers
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