An example of consecutive odd integers is 23, 25, 27, and 29. Find four consecutive odd integers with a sum of 160. Show your wo
rk. After completing the problem, write out the steps, in words, that you used to solve the problem??????????????? Please tell me the steps to so I can understand please.
Step1: Define an odd integer. Define the first odd integer as (2n + 1), for n = 0,1,2, ..., Note that n is an integer that takes values 0,1,2, and so no.
Step 2: Create four consecutive odd integers. Multiplying n by 2 guarantees that 2n will be zero or an even number. Therefore (2n + 1) is guaranteed to be an odd number. By adding 2 to the odd integer (2n+1), the next number (2n+3) will also be an odd integer.
Let the four consecutive odd integers be 2n+1, 2n +3, 2n +5, 2n +7
Step 3: require that the four consecutive integers sum to 160. Because the sum of the four consecutive odd integers is 160, therefore 2n+1 + 2n+3 + 2n+5 + 2n +7 = 160 8n + 16 = 160 8n = 144 n = 18
Because 2n = 36, the four consecutive odd integers are 37, 39, 41, 43.
Try the first four cards in order from left to right. It starts with the expression, plugs in 6 for t, does 6 * 3 first because of PEMDAS, and then does 27 - 18, which is 9.
