Let P be the plane that intersects
- x-axis at point (-5,0,0);
- y-axis at point (0,-2,0);
- z-axis at point (0,0,5).
Write the equation of the plane P:
Then
The coefficients at variables x, y and z are the coordinates of perpendicular vector to the plane. Thus
Answer: 
Answer:
hey
Step-by-step explanation:
to calculate perimeter, you require length,breadth
since points are given,find distance between points using distance formulae
<h2>root over (x2-x1)² +(
y2-y1)²</h2>
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<h3>Point H =(6,7)</h3><h3>Point I=(-6,-9)</h3><h3>Point J=(-10,-6)</h3><h3>Point G=2,10)</h3>
Now find distance between HI and IJ
HI gives the distance - length of rectangle
IJ gives the distance - breadth of rectangle
use the formulae ,2(length+breadth) to get perimeter
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HI= root over 144+256= root 400
HI=20
IJ= root over 16+9= root 25
IJ=5
PERIMETER =2(20+5)
2×25
=50
Answer:
find the area if the sector,then the area of the triangle.After that, Subtract the area of the triangle from the area of the sector
Let x = your number.
6x = x^2 - 27. Subtract 6x from each side.
0 = x^2 - 6x - 27. Factor
0 = (x-9) (x+3). Set each term equal to zero
(x+3) = 0. Subtract 3 from each side.
x = -3. This is the negative solution.
(x-9) = 0. Add 9 to each side.
x = 9. This is the positive solution.
