We need two numbers that when multiplied will give you -40 and when added will give you -3:
(x+5) (x-8) this is your answer. And you want to know the process Here it goes. And attached is a chart I made you so you can visually see what this process is telling you:
1) identify a,b, and c in the trinomial ax^2 + bx+c (in your case it's 1x^2-3x-40= x^2-3x-40)
2) write down all factor pairs of c (numbers that multiplied produce -40)
3) identify which factor pair from the previous step sums up to b
4) Substitute factor pairs into two binomials
Answer:
3x-4/14=9/10
You change the subtraction to addition
3x+4/14=9/10
Then you change the fractions to decimals
Step-by-step explanation:
Answer:
it on sale for 27%
Step-by-step explanation:
Answer:
if I'm thinkng straight integers do always have to be whole numbers but they also can be negative
Check the picture below, so the circle looks more or less like so, with a radius of 9.
![\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=9 \end{cases}\implies C=2\pi (9)\implies C\approx 57](https://tex.z-dn.net/?f=%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%20C%3D2%5Cpi%20r~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D9%20%5Cend%7Bcases%7D%5Cimplies%20C%3D2%5Cpi%20%289%29%5Cimplies%20C%5Capprox%2057)
