How to show your work using 879×8
1 answer:
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Answer:
The new points to the triangle will be:
Step-by-step explanation:
Because the reflection point is at , all x values will subtract their distances from
to get their new values. The y values remain the same.
The starting values are:
Point is 5 units away from
, so we'll subtract 5 from -1 to get the new x value:
, so
.
Point is also 5 unit away from
, so we'll subtract 5 from -1 to get the new x value:
, so
.
Point is 7 units away from
, so we'll subtract 7 from -1 to get the new x value:
, so
.
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
