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drek231 [11]
3 years ago
15

Calculate the slope of the line given the coordinates of the endpoints. (4, 10) , (6, 20) The slope is

Mathematics
1 answer:
labwork [276]3 years ago
7 0

Answer:

the slope should be 5

Step-by-step explanation:

y = 5x - 10

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IDENTIFICA EL VOLUMEN DE CADA UNA DE LAS SIGUIENTES FIGURAS
Alex17521 [72]

Answer:

Não falo espanhoooooooooooooooool

3 0
3 years ago
Given the system
Irina-Kira [14]

we have

y > -2 x + y < 4

using a graph tool

see the attached figure

The shaded area is the solution of the system

<u>Part 1) </u>Name an ordered pair that is a solution to this system and explain how you know that this is a solution point

Let

A ( -40,20)

The point A is solution of the system because the point lie on the shaded area

<u>Check</u>

If the point A is solution of the system must satisfy both system inequalities

point A

x=-40

y=20

substitute

y > -2-------> 20 > -2-------> is ok

x + y < 4----> -40+20 < 4-----> -20 < 4-----> is ok

therefore

<u>the answer Part 1) is</u>

The point A is a solution of the system

Part 2) Name an ordered pair that is not a solution to the system and explain how you know that it is not a solution

Let

B(20,20)

The point B is not solution of the system because the point not lie on the shaded area

<u>Check</u>

If the point B is not solution of the system must not satisfy both system inequalities

point B

x=20

y=20

substitute

y > -2 -------> 20 > -2-------> is ok

x + y < 4---->20+20 < 4-----> 40 < 4------> is not ok

therefore

<u>the answer part 2) is</u>

The point B is not a solution to the system

6 0
3 years ago
1. X - 18 = 23
Thepotemich [5.8K]

Answer:

  1. 41
  2. -5
  3. 42
  4. 21
  5. 4
  6. 7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
4 years ago
Dilation ( effects of changing dimensions on perimeter and area)
Archy [21]
The answer is C) 64in.
4 0
4 years ago
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