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den301095 [7]
3 years ago
12

Find the center of the circle that you can circumscribe about ABC A=(-1,-2) B=(-5,-2) C=(-1,-7)

Mathematics
1 answer:
Luda [366]3 years ago
6 0

Answer:

O : (-3,-4.5)

Step-by-step explanation:

center of circle: O (x.y)

Radius (r) = OA = OB = OC

r² = (x - (-1))² + (y - (-2))² ---- OA²  

r² = (x - (-5))² + (y - (-2))² ---- OB²

r² = (x - (-1))² + (y - (-7))² ---- OC²

OA²=OB² : (x - (-1))² + (y - (-2))² =  (x - (-5))² + (y - (-2))²

(x+1)² - (x+5)² = 0       x²+2x+1-x²-10x-25 = 0

8x = -24

x = -3

OA² = OC²   (x - (-1))² + (y - (-2))² = (x - (-1))² + (y - (-7))²

y²+4y+4 = y² +14y +49

10y = -45

y = - 4.5

O : (-3,-4.5)

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The answer please for my online class
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Answer:

B. -500

Step-by-step explanation:

\dfrac{(2a^4)^2}{a^0a^5} =

= \dfrac{2^2a^8}{a^5}

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= 4(-5)^3

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3 years ago
Amery has x books that weigh 2 pounds each and y books that weigh 3 books each. the total weight of his books is 60 pounds.write
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3 years ago
Which rules of exponents will be used to evaluate the expression. Check all that apply
julia-pushkina [17]

Hello!

The answer are:

- Product of powers.

- Power of a power.

- Negative exponents.

<h2>Why?</h2>

Let's solve it!

It's a math rule that we must solve first what's into a brake or parenthesis, so,

First: Product of powers [(7)^{5}*(7)^{3}]

According to the exponent's law, we have a product of powers case, so, we need to sum the exponents and keep the base

Exponents: 5 and 3

Base: 7

Applying it we have:

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(7)^{8}

Then,

We have a power of a power case, which involves multiplying the exponents:

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Exponents: 3 and -4

Then,

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Have a nice day!

6 0
3 years ago
Read 2 more answers
2.5t + 350 = 3t + 225? What is the soulution ?
Tanzania [10]

Answer:

t = 41.6 (the 6 is repeating)

Step-by-step explanation:

2.5t + 350 = 3t + 225

Subtract 2.5t from both sides to get:

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Now subtract 225 from both sides to get:

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Divide both sides by three.

t = 41.6 (the 6 is repeating)

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Yes they work how they work to they work
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