Let the number of type A surfboards to be ordered be x and the number of type B surfboards be y, then we have
Minimize: C = 272x + 136y
subject to: 29x + 17y ≥ 1210
x + y ≤ 50
x, y ≥ 1
From the graph of the constraints, we have that the corner points are:
(20, 30), (41.138, 1) and (49, 1)
Applying the corner poits to the objective function, we have
For (20, 30): C = 272(20) + 136(30) = 5440 + 4080 = $9,520
For (41.138, 1): C = 272(41.138) + 136 = 11189.54 + 136 = $11,325.54
For (49, 1): C = 272(49) + 136 = 13328 + 136 = $13,464
Therefore, for minimum cost, 20 type A surfboards and 30 type B surfboards should be ordered.
First bring 3x to the other side, which will give you -2y= -16-3y. Then divide everything by -2, which will give you y=8+3/2x
1) This is not an arithmetic sequence because it has n².
2) To find 5 first terms of this sequence, you can simply substitute n with 1,2,3,4, and 5, and calculate values of a(1),a(2), a(3), a(4) and a(5).
a(n) = 3n²- 1
n=1 a=3*1² - 1 = 3-1=2
n=2 a=3*2² - 1 = 11
n=3 a=3*3² - 1 =26
n=4 a=3*4² - 1 = 47
n=5 a=3*5² -1 = 74
2,11,26,47,74
Answer C. 2,11,26,47,74.
