Can someone please help me on this question
I will give brainliest
1 answer:
Answer:
A) 3 in
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
Equality Properties
<u>Geometry</u>
Surface Area of a Sphere: SA = 4πr² Diameter: d = 2r Step-by-step explanation:
<u>Step 1: Define</u>
SA = 23 in²
<u>Step 2: Find </u><em><u>r</u></em>
Substitute [SAS]: 23 in² = 4πr² Isolate <em>r </em>term: 23 in²/(4π) = r² Isolate <em>r</em>: √[23 in²/(4π)] = r Rewrite: r = √[23 in²/(4π)] Evaluate: r = 1.35288 in
<u>Step 3: Find </u><em><u>d</u></em>
Substitute [D]: d = 2(1.35288 in) Multiply: d = 2.70576 in Round: d ≈ 3 in
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