Answer:
i do not have enough information
Step-by-step explanation:
if you explain better i will gladly answer your question
sorry
The simplest form is 63/100 <span />
![\displaysyle (\sqrt 2)^{3}=(2^{\frac{1}{2}})^3=2^{\frac{1}{2} \cdot 3}=2^{\frac{3}{2}}=\sqrt {2^3}=\sqrt 8](https://tex.z-dn.net/?f=%20%5Cdisplaysyle%20%28%5Csqrt%202%29%5E%7B3%7D%3D%282%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%29%5E3%3D2%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%5Ccdot%203%7D%3D2%5E%7B%5Cfrac%7B3%7D%7B2%7D%7D%3D%5Csqrt%20%7B2%5E3%7D%3D%5Csqrt%208%20)
√8 is between 2 and 3, because 2²=4<8, but 3²=9>8. Also, our value is closer to 3 than to 2, so it is more than 2.5 and we have C and D options left.
Among these two numbers we find the one which is closer to √8.
C. 27=√729 ⇒ 2.7=√7.29
D. 28=√784 ⇒ <u>2.8=√7.84</u>
Hence our answer is D) 2.8