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Vinil7 [7]
3 years ago
10

Terry has completed 15 homework problems, and Susan has completed 9. Terry is completing 10 problems per hour, and Susan is comp

leting 12 per hour. After how many hours will Terry and susan have completed the same number of problems?
Mathematics
1 answer:
Rainbow [258]3 years ago
7 0
Let the number of hour it took them to have completed the same number of problems be x, then
15 + 10x = 9 + 12x
12x - 10x = 15 - 9
2x = 6
x = 6/2 = 3

After 3 hours, they must have completed the same number of homeworks.
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At a store 30 pieces of candy cost a total of $2.40 each piece of candy cost the same amount what is the total cost of 4 pieces
uysha [10]

Answer:

0.32

Step-by-step explanation:

First you divide 2.40 by 30 and then it gives you the cost of each individual piece of candy.then you multiply 4 by that amount.

6 0
3 years ago
Simplify (2 3/5) divided ( -3 3/4)
Ostrovityanka [42]

Flip over the second fraction

2 3/5= 13/5 ( Multiply the whole number with the denominator, 2*5=10 then add the numerator 10+3=13

-3 3/4= -15/4

13/5 * -4/15= -52/75

Answer :-52/75

4 0
3 years ago
I draw five cards from a randomly shuffled deck. What is the probability that those five cards are in either ascending or descen
Viefleur [7K]

Answer: The probability of drawing 5 cards in either ascending or descending order out of the deck of 52 standard playing cards is 0.84%.

Step-by-step explanation: We have the following cards in a deck: 1(ace), 2, 3, 4, 5, 6, 7, 8, 9, 10, 12(Jack), 13(Queen), 14(King) (thirteen different in total). There are 4 copies of each of them yielding 52 cards in total. First to draw all of the cards in the ascending order all of the drawn cards need to be different. Imagine you have 13 piles of 4 identical cards. Let us calculate the number of ways you can select 5 different ones (the order matters). First you select 5 different piles (this secures that each card is different) and this is possible to do in \frac{13!}{(13-5)!} (we use the formula for variations since the order matters). Now, each card in the pile can be selected in 4 different ways so the total number of sequences with 5 different cards is 4^5\frac{13!}{(13-5)!}. Now we select out of these sequences the clases of those that contain exactly the same cards but in different order. Only 4 of the sequences within the same class will be in ascending order out of 4*5! which is the total number of the sequences within the class! This means that we have to multiply our total number of sequences of 5 different cards by \frac{4}{4\cdot 5!}=\frac{1}{5!} and this yields the final answer of total number of ascending sequences to be

4^5\frac{13!}{(13-5)!5!}.  

The total number of possible ways to draw 5 out of 52 cards is just

\frac{52!}{(52-5)!}.

This yields for the probability

\frac{4^5\frac{13!}{(13-5)!5!}}{\frac{52!}{(52-5)!}}=0.42\%

Exactly the same calculation applies for the descending order. So the probabilty of the cards being in either ascending or descending order is just the sum of these two (the events are mutually exclusive, you cannot have both the ascending and descending order at the same time) yielding the final probability of 0.84\%.

6 0
3 years ago
PLEASE HELP ME!!!! ASAP PLEASE!
german

Answer:

We know that since it's a square, the lenght size is the same on all sides. We can simply use pythagoras theorem:

a^2 + a^2 = 13.5^2

13.5^2 = 182,25‬

182,25 : 2 (because there are 2 'a') = 91,125

<u>The square root of 91,125 is 9,55 feet.</u>

8 0
3 years ago
Using mixed numbers, write a problem in which an estimate is enough to solve the problem.​
KengaRu [80]

explain:

Estimating Differences of Fractions and Mixed Numbers

Estimating Differences of Fractions and Mixed NumbersRecall that estimation is a method for finding an approximate solution to a problem. Even when you are asked to find an exact ko, estimation is a useful way to get an idea of a reasonable solution to a problem. Once you have found an exact answer, you can check your answer against the estimate.

, estimation is a useful way to get an idea of a reasonable solution to a problem. Once you have found an exact answer, you can check your answer against the estimate.When working with fractions and mixed numbers, you can use the fraction benchmarks of 0,

, estimation is a useful way to get an idea of a reasonable solution to a problem. Once you have found an exact answer, you can check your answer against the estimate.When working with fractions and mixed numbers, you can use the fraction benchmarks of 0, 12

, estimation is a useful way to get an idea of a reasonable solution to a problem. Once you have found an exact answer, you can check your answer against the estimate.When working with fractions and mixed numbers, you can use the fraction benchmarks of 0, 12, and 1 to help you to estimate differences.

, estimation is a useful way to get an idea of a reasonable solution to a problem. Once you have found an exact answer, you can check your answer against the estimate.When working with fractions and mixed numbers, you can use the fraction benchmarks of 0, 12, and 1 to help you to estimate differences.Here are the steps for estimating the differences of fractions and mixed numbers using benchmarks.

7 0
3 years ago
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