Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
A and D that’s the answer
Answer:
x=−4/5 or x=−3
Step-by-step explanation:
Step 1: Factor left side of equation.
(5x+4)(x+3)=0
Step 2: Set factors equal to 0.
5x+4=0 or x+3=0
x=−4/5 or x=−3
Answer:
4/21
Step-by-step explanation:
Multiply 1 and 4. Then multiply 3 and 7. So 1x4=4, and 3x7=21. Therefore, the answer is 4/21. In multiplying fractions, you just multiply straight across (: (Hope this helps)
Answer:
TanA= 
and sinA=36/45
Step-by-step explanation:
Tan= opposite/adjacent
since 36 is opposite of A and 27 is adjancent to 36 your will use tanA= 36/27
Sin= opposite/hypotenuse
36 is opposite of A and 45 is the hypotenuse
