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Eva8 [605]
4 years ago
10

A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.4 gal tank

Mathematics
1 answer:
ruslelena [56]4 years ago
5 0

Given, the density of a particular brand of gasoline = 0.737 g/ml.

13.4 gallon of tank given. We have to find the mass of gasoline to fill the tank.

First we will convert 13.4 gallon to ml.

We know that 1 gallon = 3.78541 litre

And 1 litre = 1000 ml

So we can write 1 gallon = (3.78541)(1000) ml = 3785.41 ml.

13.4 gallon = (3785.41)(13.4) ml = 50724.494 ml.

Let's take there is x grams of gasoline

We know that density = (mass/ volume) = \frac{x}{50724.494}

So we can write,

0.737 =\frac{x}{50724.494}

To find x we will multiply both sides by 50724.494. we will get,

(0.737)(50724.494) =(\frac{x}{50724.494}) (50724.494)

(0.737)(50724.494) = x

37383.95 = x

So we have got the required answer.

Mass of gasoline = 37383.95 grams.

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antoniya [11.8K]

Slope intercept form is: y = mx + b


Isolate the y. First subtract 10x from both sides


10x (-10x) + 2y = 8 (-10x)


2y = -10x + 8


Isolate the y. Divide 2 from both sides and <em>all</em> terms.


(2y)/2 = (-10x + 8)/2


y = -5x + 4


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hope this helps

7 0
3 years ago
Complete the steps 4/9 divided by 1/2
DedPeter [7]

Answer: 0.88 (the 8 recurs)

Step-by-step explanation:

\frac{4}{9}÷\frac{1}{2}

\frac{4}{9}×\frac{2}{1}  (Then the the fraction should reciprocal so the values should shift to          the opposite side were 2 goes up and 1 goes down and the sign turns to the multiplication sign)

then u should multiply the two fractions which gives 8/9

next you should divide 8 by 9 which gives 0.88(the number eight is recurring which means that the number 8 keeps repeating no matter how many times you try to divide)

4 0
2 years ago
Please EXPLAIN how to get this answer so I can do it with other problems. A straight answer would be great, but I have to do abo
OLEGan [10]

Answer:

PQ = 3.58, and RQ = 10.4

Step-by-step explanation:

We are given the hypotenuse of the triangle, and an angle. Use sin and cos to solve.  

Hypotenuse = 11,

Opposite side is PQ

Adjacent side is RQ

x = 19

Sin x  = (opposite side)/(hypotenuse)

Cos x = (adjacent side)/(hypotenuse)

For PQ, this is the side opposite to the angle, so use sin,

Sin 19 = x/11

   11(Sin 19) = x

        3.58 = x        (rounded to the nearest hundredth)            

For RQ, this is the side adjacent to the angle, so use cos,

Cos 19 = x/11

   11(Cos 19) = x

        10.4 = x        (rounded to the nearest hundredth)        

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3 years ago
Can someone please help me
gavmur [86]
You can use photo math
8 0
3 years ago
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2+2= what +6 HA they cant repo this so u guys can get points
Rzqust [24]

Answer:

10

Step-by-step explanation:

2+2=4

4+6= 10

5 0
3 years ago
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