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Anit [1.1K]
3 years ago
6

3rd out of 10 questions For a cooking class, Tom earns 4 points for each meal that he cooks.

Mathematics
2 answers:
Pani-rosa [81]3 years ago
6 0
The ratio would be 1 meal : 4 points.
shtirl [24]3 years ago
3 0

Answer:

Step-by-step explanation:

jnj

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The Adventures of Huckleberry Finn, written by Mark Twain, has an ISBN of 978-014243717a, where a is the check number. What is t
Simora [160]

Answer: D. 9

Step-by-step explanation:

4 0
3 years ago
On a number line what is the difference between -3/7 and -2/3?
Yakvenalex [24]

Answer:  -5/21

Step-by-step explanation:

-3/7 & -4/6

common detonator is 42

-3/7 = -18/42 reduced to -9/21

-4/6 = -28/42 reduced to -14/21

difference between -9/21 and -14/21 = -5/21

4 0
3 years ago
Phyllis invested 50000 dollars, a portion earning a simple interest rate of 5 percent per year and the rest earning a rate of 7
Elodia [21]

Answer:

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Let

x-----> the amount invested at 5%

50,000-x -----> the amount invested at 7%

so

t=1\ year\\ I=\$2,720\\r_1=0.05\\r_2=0.07\\P_1=\$x\\P_2=\$(50,000-x)

substitute in the formula above

2,720=x(0.05*1)+(50,000-x)(0.07*1)

solve for x

2,720=0.05x+3,500-0.07x

0.07x-0.05x=3,500-2,720\\0.02x=780\\x=\$39,000

(50,000-x)=\$11,000

therefore

The amount invested at 5% was $39,000 and the amount invested at 7% was $11,000

5 0
3 years ago
A model house is built on a base then measures 9 1/4 inch. Wide and 8 4/5 inch. Long. What is the total area of the model house'
Mrac [35]
The total area would be 9 1/4 multiplied by 8 4/5 which would equal 81.4 inches
6 0
3 years ago
A class consists of 10 male and 10 female students. if four students are selected at random, without replacement, what if four s
Flura [38]
\displaystyle
|\Omega|=\binom{20}{4}=\dfrac{20!}{4!16!}=\dfrac{17\cdot18\cdot19\cdot20}{2\cdot3\cdot4}=4845\\
|A|=\binom{10}{4}=\dfrac{10!}{4!6!}=\dfrac{7\cdot8\cdot9\cdot10}{2\cdot3\cdot4}=210\\\\
P(A)=\dfrac{210}{4845}=\dfrac{14}{323}\approx4.3\%
8 0
3 years ago
Read 2 more answers
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