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Anon25 [30]
3 years ago
11

PLEASE HELPPP...When x = -1, what does y equal? A:1/3 B:Undefined C:-3​

Mathematics
1 answer:
Igoryamba3 years ago
3 0
I believe it’s undefined
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Juli2301 [7.4K]
I would love to help however you have not told us what the given function is. If you post that I would be happy to help you.
3 0
3 years ago
Solve for x. 3x/2 = 15 x = 22 1/2 x = 10 1/2 x = 10 x = 1/10
Leokris [45]

Answer:

x = 10

Step-by-step explanation:

(3x)/2 = 15 is your question.

Isolate the variable (x). Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS (Parenthesis, Exponent (& roots), Multiplication, Division, Addition, Subtraction).

First, multiply 2 to both sides

((3x)/2) = (15)(2)

3x = (15)(2)

3x = 30

Next, to isolate the variable (x), divide 3 from both sides

(3x)/3 = (30)/3

x = 30/3

x = 10

x = 10 is your answer

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8 0
3 years ago
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987 tickets sold on monday and 349 tickets sold on Tuesday
Inga [223]

Answer:

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Step-by-step explanation:

{I need more details}

7 0
3 years ago
Assume a test for a disease has a probability 0.05 of incorrectly identifying an individual as infected (False Positive), and a
Nana76 [90]

Answer:

0.00002 = 0.002% probability of actually having the disease

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test

Event B: Having the disease

Probability of having a positive test:

0.05 of 1 - 0.000001(false positive)

0.99 of 0.000001 positive. So

P(A) = 0.05*(1 - 0.000001) + 0.99*0.000001 = 0.05000094

Probability of a positive test and having the disease:

0.99 of 0.000001. So

P(A \cap B) = 0.99*0.000001 = 9.9 \times 10^{-7}

What is the probability of actually having the disease

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{9.9 \times 10^{-7}}{0.05000094} = 0.00002

0.00002 = 0.002% probability of actually having the disease

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3 years ago
What is the sum of 1/8+5/15+3/8​
Ymorist [56]

Answer:

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Step-by-step explanation:

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