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2 years ago

Please help with algebra question

Mathematics

1 answer:

ELEN [110]2 years ago

3 0

We have:
6x-y> = 5
For this case what you should do is to graph the following straight line:
6x-y = 5
Then, the solution will be the shaded region that satisfies the following inequality:
6x-y> = 5
In the shaded region you will find all the solution points.
Answer:
See attached image

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Jack made $30 mowing lawns in May and $72 mowing lawns in June. By what percent did the amount of money Jack made mowing lawns i

WARRIOR [948]

$72 - $30 = $42

It increased $42.

Now take this number and divide by the original number (first):

42 ÷ 30

This is 1.4, let's convert this to a percentage.
We now times it by 100

1.4 × 100

The answer is 140%

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3 years ago

is the equation a true statement when x equals -3 in other words is -3 a solution to the equation 6 x + 5 = 5x +8 + 2x explained

serg [7]

Answer: Yes

Step-by-step explanation: bc 6(-3)+5=5(-3)+8+2(-3)

Becomes -18+5=-15+8+-6 which equals -13 on both sides meaning -3 is a solution

5 0

2 years ago

Read 2 more answers

1. Prove or give a counterexample for the following statements: a) If ff: AA → BB is an injective function and bb ∈ BB, then |ff

Fantom [35]

Answer:

a) False. A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1

b) True

c) True

d) B = {1}, A = N, f: N ⇒ {1}, f(x) = 1

Step-by-step explanation:

a) lets use A = {1}, B = {1,2} f: A ⇒ B, f(1) = 1. Here f is injective but 2 is an element of b and |f−¹({b})| = 0., not 1. This statement is False.

b) This is True. If A were finite, then it can only be bijective with another finite set with equal cardinal, therefore, B should be finite (and with equal cardinal). If A were not finite but countable, then there should exist a bijection g: N ⇒ A, where N is the set of natural numbers. Note that f o g : N ⇒ B is a bijection because it is composition of bijections. This, B should be countable. This statement is True.

c) This is true, if f were surjective, then for every element of B there should exist an element a in A such that f(a) = b. This means that f−¹({b}) has positive cardinal for each element b from B. since f⁻¹(b) ∩ f⁻¹(b') = ∅ for different elements b and b' (because an element of A cant return two different values with f). Therefore, each element of B can be assigned to a subset of A (f⁻¹(b)), with cardinal at least 1, this means that |B| ≤ |A|, and as a consequence, B is finite.

b) This is false, B = {1} is finite, A = N is infinite, however if f: N ⇒ {1}, f(x) = 1 for any natural number x, then f is surjective despite A not being finite.

4 0

3 years ago

$2,000 loan at 8% for 5 years.

Harman [31]

Answer:

$2,800 = Principle + Interest

Step-by-step explanation:

Using PRT/100, let's find the interest.

=> 2,000 x 8 x 5/100
=> 20 x 8 x 5
=> $800

Conclusion:

Therefore, the interest plus principle is 2,000 + 800, which is $2,800.

Hoped this helped.

$BrainiacUser1357$

8 0

2 years ago

Read 2 more answers

Using the given information, give the vertex form equation for each parabola.

ollegr [7]

Answer:

Step-by-step explanation:

If you plot this point and the directrix on a coordinate plane, you can see that the directrix is 1/4 of a unit below the vertex. Since, by nature, a parabola opens in the direction opposite the directrix and "hugs" the focus, this is a positive x-squared parabola (meaning it opens upwards). The formula for this type of a parabola is, in vertex form,

$4p(y-k)=(x-h)^2$

where p is distance (in units) between the vertex and the directrix and h and k are the coordinates of the vertex. For us, p = .25, h = 7, and k = -6. Filling in our formula:

$4(.25)(y+6)=(x-7)^2$

Simplify the left side to

$1(y+6)=(x-7)^2$ which simplifies, in its entirety, to

$(x-7)^2-6=y$

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2 years ago