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mariarad [96]
2 years ago
7

Identify the equation in slope-intercept form for the line containing the point (-4,1) and (2,3)

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
7 0

Answer:

The point slope formula is

(y−y1)=m(x−x1)

Where m = the slope calculated as y2−y1x2−x1

(x1,y1)(x2,y2)

(-4 , 1) (-2 , 3)

Solve for the slope

m = 3−1−2−(−3) = 21 = m = 2

(y−3)=2(x−(−2)) Plug in known values.

y−3=2(x+2) Simplify signs

y−3=2x+4 Use Distributive property

y=−2x+4+3 isolate the y variable

answer (y = −5x+7 ) Simplify

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After triangle ACE is dilated by a factor of 6, it has an area of 180 square inches. What was its area before dilation?
Agata [3.3K]

Answer:

The area of triangle ACE before dilation is:  30 square inches

Step-by-step explanation:

We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.

  • If the scale factor > 1, the image is enlarged
  • If the scale factor is between 0 and 1, it gets shrunk
  • If the scale factor = 1, the object and the image are congruent

The length of the image can be determined by multiplying the length of the original point by a certain scale factor.

Given that after triangle ACE is dilated by a factor of 6, it has an area of 180 square inches.

Thus, it means the dilated area is 6 times the area before dilation.

Let x be the pre-dilation area

As the dilated area is 6 times the area before dilation, so

6x = 180

divide both sides by 6

6x/6 = 180/6

x = 30 square inches.

Therefore, the area of triangle ACE before dilation is:  30 square inches

4 0
3 years ago
2
Aleksandr [31]

Answer: lower bound = 9550

<u>Step-by-step explanation:</u>

Since the number is rounded to the nearest hundred, the actual value is somewhere between 9550 (which rounds up to 9600) and 9649 (which rounds down to 9600).

The lower bound is: 9550

The upper bound is: 9649

6 0
3 years ago
An object is launched from a platform. Its height (in meters), xxx seconds after the launch, is modeled by: h(x)=-5x^2+20x+60h(x
EastWind [94]
It takes 6 seconds for it to hit the ground.

0 = -5x²+20x+60

We can solve this by factoring.  First factor out the GCF, -5:

0 = -5(x²-4x-12)

Now we want factors of -12 that sum to -4.  -6(2) = -12 an -6+2 = -4:
0 = -5(x-6)(x+2)

Using the zero product property, we know that either x-6=0 or x+2=0; this gives us the answers x=6 or x=-2.  Since we cannot have negative time, x=6.
3 0
3 years ago
Read 2 more answers
A rocket is launched at t=0 seconds. Its height, in meters above sea-level, as a function of time is given by h(t)=−4.9t2+100t+3
Vikentia [17]

Answer:

see below

Step-by-step explanation:

h(t)=−4.9t2+100t+325.

The independent variable is the one that we change

t which is in seconds

The dependent variable is the result

h(t) which is in meters

4 0
3 years ago
WHOEVER GETS IT RIGHT GETS BRAINLIEST
Ierofanga [76]

think the answer is d

5 0
3 years ago
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