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castortr0y [4]
4 years ago
6

How many two-digit positive integer less than 25 have the property that they are divisible by each of their digits? List themZ

Mathematics
1 answer:
Ierofanga [76]4 years ago
8 0
This is easy, since there aren't many positive two digit integers under 25.
Just go through and check each one!

10 - not divisible by 0.
11 - divisible
12 - divisible
13 - not divisible by 3.
14 - not divisible by 4.
15 - divisible
16 - not divisible by 6.
17 - not divisible by 7.
18 - not divisible by 8.
19 - not divisible by 9.
20 - not divisible by 0.
21 - not divisible by 2.
22 - divisible
23 - not divisible by 2 or 3.
24 - divisible

To sum it up, the numbers 11, 12, 15, 22, and 24 are divisible by each of their digits.

Hope this helps (and your fortune is "Good things will come your way if you keep eating pizza.")!

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the music hall has 20 boxes on thurs 2/5 were occupied, on friday 2/4 were occupied and o saturday 8/10 were occupied. Using sym
NikAS [45]
<span><span>1.       </span>The music hall has 20 boxes :
=> on thurs 2/5 were occupied
=> on friday 2/4 were occupied
=> and on saturday 8/10 were occupied.
Let’s find out which day has the most occupied space of the music hall.
2/5 + 2/4 + 8/10 = 6/20 + 7/20 + 10/20
Thurs 2/5 were occupied
=> 6/20 = 0.3
=> 20 * 0.3 = 6 boxes
Friday 2/4 were occupied
=> 7/20 = 0.35
=> 20 * 0.35 = 7 boxes
Saturday 8/10 were occupied.
=> 10/20 = 0.5
=> 20 * .5 = 10 boxes
Thus, during Saturday has the most number of occupied boxes.</span>



8 0
3 years ago
Yea.....can sum1 help pls
vichka [17]

Answer:

208

Step-by-step explanation:

8*8=64

9*8/2=36

36*4=144

144+64=208

have a nice day :)

8 0
3 years ago
Read 2 more answers
marissa subtracted a negative number from a positive number p. Her result was negative. is that reasonable
lesantik [10]

Answer:

Yes that is reasonable

Step-by-step explanation:

As, we will take p = 12

So, the negative number = 24

So 12-24 = - 12

So therefore it's reasonable

5 0
3 years ago
4x46=
Vitek1552 [10]
Do u have a picture of the problem??
7 0
3 years ago
if a(m/3 5) is the midpoint of joining a (p^2,p) and b (q^2,q) are (5,1) find the possible values of p and q
crimeas [40]

Answer:

p^2+q^2=10

Step-by-step explanation:

p+q=2

casework

the ones i found were -1,3 and 3,-1

where is m part of this? i'm kind of confused by the beginning of the question do i have to do anything else about that?

4 0
2 years ago
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